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3 years ago

A stop sign is showing each sids measures 12.4 inch and the distance from any sides to the opposite slide is 30 inch

1 answer:

8 0

Okay, so, simply, the area of the hexagon would be 399.48 sq in

The perimeter would be 74.4 in

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If the population has gone up 20,000 in 6yr what percent is that

Sedaia [141]

I think it is 3333% #I guessed

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4 years ago

Jamie's dog eats 3/4 pound of dog food each day. How many pounds of dog

Lena [83]

Answer:

The dog will eat 3 lbs

Step-by-step explanation:

Take the amount eaten per day and multiply by the number of days

3/4 * 4 = 3

The dog will eat 3 lbs

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3 years ago

Read 2 more answers

If x=3 then y=21. What is the value of x when y=105

NARA [144]

Answer:

0.6

Step-by-step explanation:

If Y=105 you would divide 105 by the original Y which was 21, therefore getting 5. With that 5 we would divide 3 by 5 because that's what we did with the Y and then we get 0.6. hope this helped! xx

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3 years ago

Write the fractional equivalent (in reduced form) of each number. PIC BELOW-

geniusboy [140]

Answer:

1.1/10

2.1/6

3.3/5

4.2/3

8 0

3 years ago

An ellipse has foci located at (2,4) and (2,16) and vertices located at (2,0) and (2,20) this ellipse is vertical

pochemuha

Answer:

The equation of the ellipse is $\frac{(x-2)^{2}}{8^{2}}+\frac{(y-10)^{2}}{10^{2}} = 1$ .

Step-by-step explanation:

The statement is incomplete, the most probable outcome may be the equation of the ellipse based on information given.

The equation of an ellipse whose major axis is vertical and is centered at a point different from origin is defined by:

$\frac{(x-h)^{2}}{b^{2}} + \frac{(y-h)^{2}}{a^{2}} = 1$ (1)

Where:

$(h,k)$ - Coordinates of the center of the ellipse.

$(x,y)$ - Coordinates of a point in the line of the ellipse.

$a$ - Length of the major semiaxis.

$b$ - Length of the minor semiaxis.

The coordinates of the center of the ellipse is midpoint of the segment between vertices, which are collinear with foci:

$(h,k) = \frac{1}{2}\cdot V_{1} (x,y) + \frac{1}{2}\cdot V_{2}(x,y)$ (1)

Where $V_{1} (x,y)$ and $V_{2} (x,y)$ are the coordinates of the vertices.

If we know that $V_{1} (x,y) = (2,0)$ and $V_{2} (x,y) = (2, 20)$ , then the coordinates of the center ellipse are:

$(h,k) = (2, 10)$

The length of the semimajor axis can be determined by using the following vectorial expression, which is equivalent to the Pythagorean Theorem:

$a = \sqrt{[(h,k)-V_{1}(x,y)]\,\bullet\,[(h,k)-V_{1}(x,y)]}$ (2)

If we know that $(h,k) = (2, 10)$ and $V_{1} (x,y) = (2,0)$ , then the length of the semimajor axis is:

$a = \sqrt{(2-2)^{2}+(10-0)^{2}}$

$a = 10$

And the length of the minor semiaxis is found by means of this Pythagorean identity:

$b = \sqrt{a^{2}-c^{2}}$ (3)

Where $c$ is the length between the center and any of the foci. This distance can be found by using this vectorial formula:

$c = \sqrt{[(h,k)-F_{1}(x,y)]\,\bullet\,[(h,k)-F_{1}(x,y)]}$ (4)

If we know that $(h,k) = (2, 10)$ and $F_{1} (x,y) = (2,4)$ , then the length between the center and any of the foci is:

$c = \sqrt{(2-2)^{2}+(10-4)^{2}}$

$c = 6$

And the length of the minor semiaxis is:

$b = \sqrt{10^{2}-6^{2}}$

$b = 8$

FInally, the equation of the ellipse is $\frac{(x-2)^{2}}{8^{2}}+\frac{(y-10)^{2}}{10^{2}} = 1$ .

6 0

3 years ago