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3 years ago

A stop sign is showing each sids measures 12.4 inch and the distance from any sides to the opposite slide is 30 inch

1 answer:

8 0

Okay, so, simply, the area of the hexagon would be <span>399.48 sq in

The perimeter would be </span><span>74.4 in</span>

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PLEASE HURRY IM BEING TIMED!! WILL GIVE BRAINLIEST FOR THE FIRST PERSON TO ANSWER!!!!

photoshop1234 [79]

Answer:

Step-by-step explanation:

Irrational means it can't be written as a fraction.

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3 years ago

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otez555 [7]

Answer:

option 4 and 6

Step-by-step explanation:

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3 years ago

Read 2 more answers

A study showed that the ratio of the number of people who get their news from social media to the number of people who their new

Kitty [74]

Answer: 240 people get the news from social media

Step-by-step explanation:

The ratio of the number of people who get their news from social media to the number of people who their news elsewhere is 3:7

Total ratio is the sum of the proportion of those that get their news from social media and those that got their news elsewhere.

It becomes 3+7 = 10

Total number of people in the town is 800

To determine the number of people that got their news from social media, we will divide the proportion of those that get their news from social media by the total ratio and multiply by the total number of people in the town. It becomes

3/10 × 800 = 240

6 0

3 years ago

Solve 5y'' + 3y' – 2y = 0, y(0) = 0, y'(0) = 2.8 y(t) = 0 Preview

mario62 [17]

Answer: The required solution is

$y(t)=-\dfrac{7}{3}e^{-t}+\dfrac{7}{3}e^{\frac{1}{5}t}.$

Step-by-step explanation: We are given to solve the following differential equation :

$5y^{\prime\prime}+3y^\prime-2y=0,~~~~~~~y(0)=0,~~y^\prime(0)=2.8~~~~~~~~~~~~~~~~~~~~~~~~(i)$

Let us consider that

$y=e^{mt}$ be an auxiliary solution of equation (i).

Then, we have

$y^prime=me^{mt},~~~~~y^{\prime\prime}=m^2e^{mt}.$

Substituting these values in equation (i), we get

$5m^2e^{mt}+3me^{mt}-2e^{mt}=0\\\\\Rightarrow (5m^2+3y-2)e^{mt}=0\\\\\Rightarrow 5m^2+3m-2=0~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{since }e^{mt}\neq0]\\\\\Rightarrow 5m^2+5m-2m-2=0\\\\\Rightarrow 5m(m+1)-2(m+1)=0\\\\\Rightarrow (m+1)(5m-1)=0\\\\\Rightarrow m+1=0,~~~~~5m-1=0\\\\\Rightarrow m=-1,~\dfrac{1}{5}.$

So, the general solution of the given equation is

$y(t)=Ae^{-t}+Be^{\frac{1}{5}t}.$

Differentiating with respect to t, we get

$y^\prime(t)=-Ae^{-t}+\dfrac{B}{5}e^{\frac{1}{5}t}.$

According to the given conditions, we have

$y(0)=0\\\\\Rightarrow A+B=0\\\\\Rightarrow B=-A~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)$

and

$y^\prime(0)=2.8\\\\\Rightarrow -A+\dfrac{B}{5}=2.8\\\\\Rightarrow -5A+B=14\\\\\Rightarrow -5A-A=14~~~~~~~~~~~~~~~~~~~~~~~~~~~[\textup{Uisng equation (ii)}]\\\\\Rightarrow -6A=14\\\\\Rightarrow A=-\dfrac{14}{6}\\\\\Rightarrow A=-\dfrac{7}{3}.$