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3 years ago

In the cafeteria 100 milk cartons were put out and 27 remained..what is the ratio of milk cartons taken to total milk cartons?

1 answer:

8 0

If they started with 100 and 27 remained, then (100 - 27) = 73 were taken.

ratio of milk cartons taken to total milk cartons = 73/100 or 73:100 or 73 to 100

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Add together 2350mm 3.42cm 11/2m and 1.45m

Artyom0805 [142]

9.3342meters because you convert 2350mm into m which is 2.35m, + and also convert 3.42cm to m which is 0.0342 then + 1.45m +11/2m= 9.3342m

6 0

3 years ago

Beginning in 2000, an orchestra increased its ticket price by a constant amount each year until 2010.

Scilla [17]

Answer:

$35.50

Step-by-step explanation:

55.50-48= 7.5

2008-2005 = 3

7.5 divided by 3 = 2.5 per year

2005-2000 = 5 multipled by 2.5 = 12.5

48-12.5=35.5

6 0

2 years ago

What is the result of converting 81 inches to feet remember there are 12 inches in a foot?

AlekseyPX

81 inches converted to feet is 6.75 feet

7 0

3 years ago

Read 2 more answers

Choose the best coordinate system to find the volume of the portion of the solid sphere rho <_4 that lies between the cones φ

MrRissso [65]

Answer:

So, the volume is:

$\boxed{V=\frac{128\sqrt{2}\pi}{3}}$

Step-by-step explanation:

We get the limits of integration:

$R=\left\lbrace(\rho, \varphi, \theta):\, 0\leq \rho \leq 4,\, \frac{\pi}{4}\leq \varphi\leq \frac{3\pi}{4},\, 0\leq \theta \leq 2\pi\right\rbrace$

We use the spherical coordinates and we calculate a triple integral:

$V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}}\int_0^4 \rho^2 \sin \varphi \, d\rho\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \left[\frac{\rho^3}{3}\right]_0^4\, d\varphi\, d\theta\\\\V=\int_0^{2\pi}\int_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \sin \varphi \cdot \frac{64}{3} \, d\varphi\, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} [-\cos \varphi]_{\frac{\pi}{4}}^{\frac{3\pi}{4}} \, d\theta\\\\V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\$

we get:

$V=\frac{64}{3} \int_0^{2\pi} \sqrt{2} \, d\theta\\\\V=\frac{64\sqrt{2}}{3}\cdot[\theta]_0^{2\pi}\\\\V=\frac{128\sqrt{2}\pi}{3}$

So, the volume is:

$\boxed{V=\frac{128\sqrt{2}\pi}{3}}$

4 0

2 years ago

What are the correct answers?

Delvig [45]

1. y= -x - 15
2. y= -4x + 1/2
3. y= 2x + 1
4. y= 2/3x + 3
5. y= -1/2x - 4
6. y= -3x + 13

Glad I could help

8 0

2 years ago