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2 years ago

Ghicitori despre reguli de politete

Mathematics

1 answer:

Reptile [31]2 years ago

5 0

Scoate pielea mea si am obiceiul plange, dar va fi. ce sunt eu?

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{(-3,1),(0,1),(3,1)}<br> Domain=<br> Range=<br> Function?

Alecsey [184]

Answer:

Domain : { -3, 0, 3}

Range : { 1 , 1 , 1 }

Function : These set of ordered pairs are functions as every x-value has only one y-value associated with it.

4 0

2 years ago

Find the volume of the garden shed

Leno4ka [110]

Answer:

47.3 m³

Step-by-step explanation:

The garden shed is made up of a rectangular prism and a pyramid.

<h3><u>Volume of a rectangular prism</u></h3>

$\begin{aligned}\textsf{Volume of a rectangular prism}&=\sf width \times length \times height\\&=4 \times 4 \times 2\\&=16 \times 2\\&=32\;\; \sf m^3\end{aligned}$

<h3><u>Volume of a pyramid</u></h3>

<u />

From inspection of the given diagram, the slant height of the pyramid is 3.5 m.

Calculate the perpendicular height of the pyramid using Pythagoras Theorem:

$\begin{aligned}\implies a^2+b^2&=c^2\\2^2+h^2&=3.5^2\\h^2&=8.25\\h&=\sqrt{8.25}\;\; \sf m\end{aligned}$

Therefore:

$\begin{aligned}\textsf{Volume of a pyramid}&=\dfrac{\sf length \times width \times height}{3}\\\\&=\dfrac{\sf 4 \times 4 \times \sqrt{8.25}}{3}\\\\& = 15.31883372\;\; \sf m^3\end{aligned}$

<h3><u>Volume of the garden shed</u></h3>

$\begin{aligned}\implies \textsf{Volume of shed}&=\textsf{Volume of rectangular prism}+\textsf{Volume of pyramid}\\&=32+15.31883372\\& = 47.3\;\; \sf m^3\;(nearest\;tenth)\end{aligned}$

6 0

1 year ago

Read 2 more answers

HELP ME PLEASE!!!!!!!!

lozanna [386]

Answer:

Step-by-step explanation:

use a proportion

( 3/4 ) / 1 1/8 = ( 4/4) / x teaspoons

x = 1.5

3 0

3 years ago

an amusement park charge 35.50 for admission.on saturday,6,789 people visited the park.about how much money did the park earn fr

sp2606 [1]

6,789
-
35.50
______
32.39

3 0

3 years ago

Read 2 more answers

Simplify. (x6 y3)(−8xy2)(−6x3)

meriva

When simplifying this, we would have to take this little by little in serious steps and not only this, but to also take notice of the use of <u>pemdas</u> and to make sure that we take each step carefully.

We first would <u></u><u>(first)</u> simplify the following:

$(((x^6)*(y^3))*(0-(8x*(y^2))))*(0-(2*3x^3)) \\ \\ then \ we \ would \ do . . . . \\ \\ x^7 \ multiplied \ by \ x^3 \ = x^(^7^ +^ 3^) = \ x^1^0 \\ \\ (last \ step).... \\ \\ 2^3 \ multiplied \ by \ 2^1 = 2^(^3^ +^ 1^) = 2^4 \\ \\ \Longrightarrow \ (your \ answer) \\ \\ \boxed{\bf{ (2^4*3x^1^0y^5)}}$

7 0

3 years ago