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4 years ago

The area of a triangle is found by the formula A = 1/2bh

Mathematics

2 answers:

Margarita [4]4 years ago

6 0

. dances aob equal a/.5xh edge I had to work it out and this is what the answer he got thank you

Drupady [299]4 years ago

3 0

B = (2A)/h . You could technically use the formula b = A/(0.5h), but then you'd have a fraction in a fraction.

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I am confused please help

Otrada [13]

Answer:

3 tiles will not fit together.

Step-by-step explanation:

Measure of an Interior angle of a polygon = $\frac{(n-2)\times 180}{n}$

Here, n = number of sides of the polygon

Therefore, measure of the interior angles of a regular hexagon,

A = $\frac{(6-2)\times 180}{6}$

A = 120°

Similarly, interior angle of the regular pentagon,

B = $\frac{(5-2)\times 180}{5}$

B = 108°

Now m∠A + m∠B + m∠C = 360°

m∠C = 360° - (120° + 108°)

= 132°

To fit the given three tiles perfectly, interior angle (∠D) of the third Octagonal tile should be 132°.

D = $\frac{(8-2)\times 180}{8}$

D = 135°

m∠C ≠ m∠D

Therefore, 3 tiles will not fit together.

8 0

3 years ago

What is the volume of this container?

Ostrovityanka [42]

Answer:

105 feet cubed

Step-by-step explanation:

1/2 cubed is 0.125 Since there are 840 wooden blocks, .125x840 is 105 feet cubed

7 0

3 years ago

svetoff [14.1K]

Answer:

1/2 ornament in an hour

Step-by-step explanation:

Given

$Orna\ ments = 2$

$Time = 4$

Required

Determine the ornaments per hour

This question implies that we calculate the unit rate.

$Unit\ Rate = \frac{Orna\ ments}{Time}$

Substitute values for Time and number of ornaments

$Unit\ Rate = \frac{2}{4}$

$Unit\ Rate = \frac{1}{2}$

<em>This implies that Constance can decorate 1/2 ornaments in an hour</em>

3 0

3 years ago

A random variable x follows a normal distribution with mean d and standard deviation o=2. It is known that x is less than 5 abou

Vaselesa [24]

Answer:

The mean of this distribution is approximately 3.96.

Step-by-step explanation:

Here's how to solve this problem using a normal distribution table.

Let $z$ be the

$\displaystyle z = \frac{x - \mu}{\sigma}$ .

In this question, $x = 5$ and $\sigma = 2$ . The equation becomes

$\displaystyle z = \frac{5 - \mu}{2}$ .

To solve for $\mu$ , the mean of this distribution, the only thing that needs to be found is the value of $z$ . Since

The problem stated that $P(X \le 5) = 69.85\% = 0.6985$ . Hence, $P(Z \le z) = 0.6985$ .

The problem is that the normal distribution tables list only the value of $P(0 \le Z \le z)$ for $z \ge 0$ . To estimate $z$ from $P(Z \le z) = 0.6985$ , it would be necessary to find the appropriate

Since $P(Z \le z) = 0.6985$ and is greater than $P(Z \le 0) = 0.50$ , $z > 0$ . As a result, $P(Z \le z)$ can be written as the sum of $P(Z < 0)$ and $P(0 \le Z \le z)$ . Besides, $P(Z < 0) = P(Z \le 0) = 0.50$ . As a result: