All categories

4 years ago

Please help! if anybody is good at equivalent polynomial expressions please help!!

Mathematics

2 answers:

dusya [7]4 years ago

8 0

5x +15+25x +75=0
5(× +3) + 5 (5× +15)

Readme [11.4K]4 years ago

5 0

Pull out a 5 from the first parenthesis
(5x+15) = 5(x+3)

Pull out a 25 from the second parenthesis
(25x+75) = 25(x+3)

(5x+15) + (25x+75) = your first answer = 5(x+3) + 25(x+3)

You might be interested in

X^2 + 1/2x + = 2 + Help please

Gennadij [26K]

Answer:

Step 2:

For Completing the square,

$(\frac{1}{2} coefficient\ x)^{2} =(\frac{1}{2}\times \frac{1}{2})^{2}=\frac{1}{16}$

Add half coefficient of x square on both the side we get

$x^{2}+\dfrac{x}{2}+\frac{1}{16}=2+\frac{1}{16}$

Step-by-step explanation:

Solve:

$2x^{2}+x-4=0$

$2x^{2}+x=4$

Solution:

Step 1:

Dividing both the side by two we get

$x^{2}+\dfrac{x}{2}=2$

Step 2:

For Completing the square,

$(\frac{1}{2} coefficient\ x)^{2} =(\frac{1}{2}\times \frac{1}{2})^{2}=\frac{1}{16}$

Add half coefficient of x square on both the side we get

$x^{2}+\dfrac{x}{2}+\frac{1}{16}=2+\frac{1}{16}$

Step 3:

We know $(a +b)^{2} = a^{2}+2ab +b^{2}$

$(x+\frac{1}{4})^{2}=\frac{33}{16} \\ \\(x+\dfrac{1}{4})=\pm \sqrt{\dfrac{33}{16}} \\\\x=-\dfrac{1}{4}\pm \sqrt{\dfrac{33}{16}}$

6 0

4 years ago

Solve the system of equations. 2y – 3x = -27 5y + 3x = 6 What is y?

Volgvan

Answer:

Look the picture

Have a nice day

can I be brainliest

4 0

3 years ago

Read 2 more answers

Referring to the figure, find the value of x

bekas [8.4K]

Answer:I think it’s 75 divided by 5

Step-by-step explanation:

8 0

4 years ago

Triangle RST is translated 6 units to the left and 4 units up to create triangle R’S’T’

Dahasolnce [82]

Answer:

B (x,y) —> (-6x,4y)

Step-by-step explanation:

6 is moving left which is negative

4 is moving up which is positive

5 0

3 years ago

Can someone please answer. There is one problem. There's a picture. Thank you!

Katen [24]

Circumference of the circle = 2πr
32 = 2*22/7*r
32*7/2*22 =r
5.09 =r
5.1 (approx) = r

7 0

3 years ago