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ivolga24 [154]
3 years ago
6

PLEASE HELP IVE BEEN WAITING FOR 4 HOURS AND STILL NO ANSWER micheal earns a base salary of $100 every week with an additional %

13 commission on everything he sells if micheal sold $6050.00 worth of items last week what was his total pay
Mathematics
2 answers:
Zarrin [17]3 years ago
6 0
I think you would take %13 of $6050.00 and add that with the $100 he gets every week so the percentage would be $786.5 and add that with the initial hundred so $886.5 i think this is the answer it might not be right
-Dominant- [34]3 years ago
3 0
I helped you with a previous problem that was almost exactly the same as this one.  Did you take notes on the previous problem so that you would have some reference to help you do later problems?

Briefly, Total Pay = $100 + 0.13(total of sales)
                            = $100 + 0.13($6050) = ?

This is a linear relationship.  Initial value was $100 and commissions are 13% of the total of sales.
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No

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2. (Red) vertical -2, horizontal 3
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3. (Blue) vertical 4, horizontal 6
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2 years ago
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3 years ago
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Use the sample data and confidence level to construct the confidence interval estimate of the population proportion p. n=500, x=
DiKsa [7]

Answer:

0.3581<x<0.4429

Step-by-step explanation:

Using the formula for calculating the confidence interval of the population proportion p expressed as:

Confidence interval = p ± Z * √p(1-p)/n

p is the population proportion = x/n

p = 200/500

p = 0.4

Z is the z-score at 95% CI = 1.96

n is the sample size = 500

Substituting the given parameters into the formula we will have;

Confidence interval = 0.4 ± 1.96 * √p(1-p)/n

Confidence interval = 0.4 ± 1.96 * √0.4(0.6)/500

Confidence interval = 0.4 ± 1.96 * √0.24/500

Confidence interval = 0.4 ± 1.96 * √0.00048

Confidence interval = 0.4 ± 1.96 * 0.0219

Confidence interval = 0.4±0.04294

Confidence interval = (0.3571, 0.4429)

Hence the confidence interval of the population mean is 0.3581<x<0.4429

5 0
3 years ago
A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
2 years ago
A grocer can buy strawberries for $1.38 per pound. write an equation relating c, the cost, and p, the pounds of strawberries.
slamgirl [31]

Answer:

1.38p=C

Step-by-step explanation:

each pound is $1.38 and pounds is p they have to equal to C, the total.

5 0
3 years ago
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