Answer:
Step-by-step explanation:
I assume your equation to solve is
When we have a product of two factors equal to zero,
The solution is either A = 0 or B = 0.
In this case, this means that we can break the equation into two equations:
Solving the first one, we get:
For the second one, we rewrite it as:
And we see that this equation has two solutions:
Therefore, the three solutions are:
Step 1) Draw a line from point F to point S. A rectangle forms (rectangle FSCW)
Step 2) Find the area of this rectangle. The area is 18 square units because it is 2 units high and 9 units across (9*2 = 18). You can count out the spaces or you can note how we go from x = -4 to x = 5 so subtracting the values gives -4-5 = -9 which has an absolute value of 9.
Step 3) Find the area of triangle FSN. The base is 9 units and the height is 6 units (count out the spaces or subtract y values). So the area is A = b*h/2 = 9*6/2 = 54/2 = 27
Step 4) Add up the area of the rectangle to the area of the triangle: 18+27 = 45
Final Answer: 45 square units
note: another way to find the answer is to find the area of rectangle WABC where point A is at (-4,4) and point B is at (5,4). Then subtract off the triangular areas of AFN and BNS
we have
Group terms that contain the same variable, and move the constant to the opposite side of the equation
Combine like terms
Divide by 
both sides
therefore
<u>the answer is</u>
the value of p in the linear equation is 
area = length times width, so length = area / width
5 1/5 mi^2 5.2 mi^2
Here, length = ------------------- = --------------- = 2.66666... mi = 2 2/3 mi (answer)
1 19/20 mi 1.95 mi
