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arlik [135]
3 years ago
13

Rachael's backyard swimming pool is being emptied by a pump. The amount of water in the pool (W, measured in gallons) at any tim

e (t, measured in hours) is given by the following equation:
W = -250t + 9000

a. How many gallons of water are being pumped out each hour? Explain.

b. After 11 hours, how much water is left in the pool? Explain.

c. How much water was in the pool at the start? Explain.

d. How long will it take the pool to empty? Explain.
Mathematics
1 answer:
trapecia [35]3 years ago
6 0
A 250 1 times 250 substract by 9000 gives 8750 them find loss of water by 9000 substracted by 8750
b 6250 11 times 250 substract by 9000 gives 6250.
c 9000 t=0 since no water it's being pumped out so answer is 9000
d 36 hours times 250 is 9000
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Answer:

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Step-by-step explanation:

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In a class of 18 students, 5 are math majors. A group of four students is chosen at random. (Round your answers to four decimal
ss7ja [257]

Answer:

(a) 0.2721

(b) 0.7279

(c) 0.2415

Step-by-step explanation:

(a) If we choose only one student, the probability of being a math major is \frac{5}{18} (because there are 5 math majors in a class of 18 students). So, the probability of not being a math major is \frac{18}{18} - \frac{5}{18} = \frac{13}{18} (we subtract the math majors of the total of students).

But there are 4 students in the group and we need them all to be not math majors. The probability for each one of not being a math major is \frac{13}{18} and we have to multiply them because it happens all at the same time.

P (no math majors in the group) = \frac{13}{18} *\frac{13}{18}*\frac{13}{18}*\frac{13}{18} = (\frac{13}{18}) ^4 = 0.2721

(b) If the group has at least one math major, it has one, two, three or four. That's the complement (exactly the opposite) of having no math majors in the group. That means 1 = P (at least one math major) + P (no math major). We calculated this last probability in (a).

So, P (at least one math major) = 1 - P(no math major) = 1 - 0.2721 = 0.7279  

(c) In the group of 4, we need exactly 2 math majors and 2 not math majors. As we saw in (a), the probability of having a math major in the group is 5/18 and having a not math major is \frac{13}{18}. We need two of both, that's \frac{5}{18}*\frac{5}{18}*\frac{13}{18}*\frac{13}{18}. But we also need to multiply this by the combinations of getting 2 of 4, that is given by the binomial coefficient \binom{4}{2}.

So, P (exactly 2 math majors) = \binom{4}{2}*(\frac{5}{18} )^2*(\frac{13}{18})^2 = \frac{4!}{2!2!}*\frac{25}{324}*\frac{169}{324} = 0.2415

7 0
4 years ago
Winton was givin $14 to spend at a school fair he spent 3/7 playing games how much money is lift
Ksivusya [100]
<h3><u>Question:</u></h3>

Winton was given $14 to spend at a school fair he spent 3/7 playing games how much money is left

<h3><u>Answer:</u></h3>

Amount left with winton is $ 8

<h3><u>Solution:</u></h3>

Given that Winton was given $14 to spend at a school fair

He spent \frac{3}{7} playing games

To find: money left with Winton

From given information,

Money given to Winton = $ 14

Amount spent on games = \frac{3}{7}

Thus we can say,

Amount spend on games = \frac{3}{7} of total money he has

\rightarrow \frac{3}{7} \times 14 = 3 \times 2 = 6

Thus he spend $ 6 on playing games

<em><u>Money left with Winton:</u></em>

Money left = total money he had - money spent on playing games

Money left = 14 - 6 = 8

Thus amount left with winton is $ 8

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3 years ago
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