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2 years ago

What are the 4-factor pairs of 56?

Mathematics

1 answer:

nika2105 [10]2 years ago

4 0

Answer:

7 and 8, 2 and 28, 1 and 56, 4 and 14

Step-by-step explanation:

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2 years ago

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The pendulum swings at an arc of 30 cm and its successive swings reduced to 10% of the previous swings. What is the total distan

OleMash [197]

Answer:

$S_g= 33.333cm$

Step-by-step explanation:

From the question we are told that

Arc of 30 cm

10% reduction after each swing

Generally sum of geometric sequence is given by the equation

$S_g=\frac{a(1-r^n)}{1-r}$

Mathematically solving for total distance traveled we have

$S_g=\frac{30(1-(0.10^5)}{1-(0.10)}$

$S_g=\frac{30}{0.9}$

Therefore the total distance traveled by the pendulum after 5 swings

$S_g= 33.333cm$

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3 years ago

Find the inertia tensor for an equilateral triangle in the xy plane.

ivanzaharov [21]

Find the inertia tensor for an equilateral triangle in the xy plane. Take the mass of the triangle to be M and the length of a side of the triangle to be b. Express your answer below as pure numbers in units of Mb^2. Place the origin on the midpoint of one side and set the y-axis to be along the symmetry axis.

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2 years ago

1212154545454 121 4654546+56546546464454-5454881/3148486*5

lesya692 [45]

Usually when you add big numbers together, you get a result of exponents involved :) answer for your question : 1.212154551 e^22

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3 years ago

A scientist had 3 1/2 liters of vinegar. He poured 2/3 of the vinegar into beaker. He then used 3/5 of the vinegar in the beaker

valentinak56 [21]

Answer:

A)2100 ml

Step-by-step explanation:

Given total vinegar is 3 1/2 liters and the used vinegar is 3/5 of the vinegar in the beaker:

#First calculate the amount of vinegar not poured in the beaker:

$V_o=V_t-V_b\\\\=3\frac{1}{2}(1-\frac{2}{3})\\\\=1\frac{1}{6}$

#Calculate amount of vinegar used in experiment:

$V_b=\frac{2}{3}V_t=\frac{2}{3}(3\frac{1}{2})=2\frac{1}{3}\\\\V_u=\frac{3}{5}V_b=\frac{3}{5}\times 2\frac{1}{3}=1\frac{2}{5}$

#The unused vinegar is therefore calculated by subtracting the used vinegar from the total at the start of the experiment:

$V_r=V_t-V_u\\\\=3\frac{1}{2}-1\frac{2}5}\\\\=2\frac{1}{10}\times 1000\ ml\\\\=2100\ ml$

Hence, the unused vinegar is 2100 ml

8 0

3 years ago