Simplify: x+2/x2-6x-16 ÷ 1/9x

1 answer:

8 0

$\dfrac{x+2}{x^2-6x-16}:\dfrac{1}{9x}=\dfrac{x+2}{x^2-8x+2x-16}\cdot9x=\dfrac{x+2}{x(x-8)+2(x-8)}\cdot9x\\\\=\dfrac{x+2}{(x-8)(x+2)}\cdot9x=\dfrac{1}{x-8}\cdot9x=\dfrac{9x}{x-8}$

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