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nexus9112 [7]
3 years ago
14

Simplify the Matrix Operation 4[-4 5 -6]

Mathematics
1 answer:
Doss [256]3 years ago
4 0

Answer:

[-16 20 -24].

Step-by-step explanation:

4[-4 5 -6]

= [4*-4 4*5 5*-6]

=  [-16 20 -24].

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Y=mx+b // standard form

3x=12-2y
2y=-3x+12
y=-3/2x+12/2
y=-3/2x+6

So the answer is: y = -3/2x+6
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Find value of P and Q
ch4aika [34]

Answer:

P= 6 \frac{1}{7}\\\\Q = 4 \frac{2}{7}

Step-by-step Explanation

\frac{5 + 3 \sqrt{2} }{5 - 3 \sqrt{2} }  = P+Q\sqrt 2 \\  \\  \frac{(5 + 3 \sqrt{2}) }{(5 - 3 \sqrt{2}) }  \times  \frac{(5 + 3 \sqrt{2}) }{(5   +  3 \sqrt{2} )} = P+Q\sqrt 2 \\  \\  \frac{ {(5 + 3 \sqrt{2} )}^{2} }{ {(5)}^{2}  - (3 \sqrt{2})^{2}  }  = P+Q\sqrt 2 \\  \\ \frac{ {5}^{2} +  {(3 \sqrt{2} )^{2}  + 2.5.3 \sqrt{2} } }{25 - 9 \times 2} = P+Q\sqrt 2 \\  \\\frac{ 25 + 18  + 30 \sqrt{2}  }{25 - 18} = P+Q\sqrt 2 \\  \\\frac{ 43  + 30 \sqrt{2}  }{7} = P+Q\sqrt 2 \\  \\ \frac{43}{7}  +  \frac{30 }{7} \sqrt{2}  = P+Q\sqrt 2 \\  \\ equating \: like \: terms \: on \: both \: sides \\  \\ P =  \frac{43}{7}   \\  \\ \huge \red { \boxed{ P= 6 \frac{1}{7}}}  \\  \\ Q =  \frac{30}{7}  \\  \\ \huge  \orange { \boxed{ Q = 4 \frac{2}{7} }}

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3 years ago
The figure shown is a rectangle. The green shape in the figure is a square. The blue and white shapes are rectangles, and the ar
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Answer:

A. (2 × 6) + (3 × 8) + 6²

72 sq. inches.

B. 9 in. by 8 in.

Step-by-step explanation:

The white shape has dimensions of 2 in. by 6 in. and the green shape is a square.

So, the dimension of the green shape is 6 in. by 6 in.

Therefore, the length of the blue shape is (6 + 2) = 8 in.

Now, given that the area of the blue shape is 24 sq. in.

So, the width of the blue shape is \frac{24}{8} = 3 in.

Now, if we consider the total figure, then area of the entire figure = area of the  white shape + area of the green shape + area of the blue shape.

= (2 × 6) + (3 × 8) + 6² (Answer)

= 12 + 24 + 36  

= 72 sq, inches. (Answer)

Now, the length of the entire figure is (6 + 3) = 9 in. and width of the entire figure is (2 + 6) = 8 in.

Therefore, the dimensions of the entire figure will be 9 in. by 8 in. (Answer)

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4 years ago
Write a word problem in wich the starting number is in the hundereds and the awnser is 4 tickets
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Answer:

Choir kids are selling tickets to their show. There needs to be 400 tickets sold ,and there are 100 kids to sell them. How many tickets does each kid need to sell?

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####HHGUGnu

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