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3 years ago

Construct a truth table for p^(q^r)

Mathematics

1 answer:

kiruha [24]3 years ago

8 0

Answer:

check.

Step-by-step explanation:

I did the table in the picture below. To understand it you only need to know that the ^ only is true when both propositions (left and right) are true.

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10. Liliana makes and sell homemade bracelets. She made a profit of $75 last week. She donated some bracelets to charity. This w

Leona [35]

Answer:

75+(-50)=75-50

Step-by-step explanation:

-let x be the profit made last week and y be the profit made this week.

-The two week profit/ loss is given as:

$Profit=x+y$

#We substitute actual values to calculate the profit/loss made:

$Profit=x+y\\\\=75+(-50)\\\\=75-50\\\\=\$25$

Hence, the two-week combined profit is $25.00

4 0

3 years ago

For every 5 green apples there are 2 red apples what is the raito

spin [16.1K]

Answer:

5:2

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

11) Ms. Ripa's family is planning to come visiting her from New York. She hopes to take

Natasha_Volkova [10]

$88

Explanation:
Adults $12x5 = 60
Child $7x 4=28
60+28=88

5 0

3 years ago

Question 8 Find the unit vector in the direction of (2,-3). Write your answer in component form. Do not approximate any numbers

slamgirl [31]

Answer:

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

Step-by-step explanation:

Let be $\vec u = (2,-3)$ , its unit vector is determined by following expression:

$\hat {u} = \frac{\vec u}{\|\vec u \|}$

Where $\|\vec u \|$ is the norm of $\vec u$ , which is found by Pythagorean Theorem:

$\|\vec u\|=\sqrt{2^{2}+(-3)^{2}}$

$\|\vec u\| = \sqrt{13}$

Then, the unit vector is:

$\hat{u} = \frac{1}{\sqrt{13}} \cdot (2,-3)$

$\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$

The unit vector in component form is $\hat{u} = \left(\frac{2}{\sqrt{13} },-\frac{3}{\sqrt{13}} \right)$ or $\hat{u} = \frac{2}{\sqrt{13}}\,i-\frac{3}{13}\,j$ .

6 0

3 years ago

Cot²3x - 3cot3x +2 = 0<br> cotx = t<br> what equation for t

kumpel [21]

Answer:

Step-by-step explanation:

cot²(3x)=y

y²-3y+2=0

y²-y-2y+2=0

y(y-1)-2(y-1)=0

(y-1)(y-2)=0

y=1,y=2

cot3x=1

tan 3x=1=tan (π/4)=tan (nπ+π/4)

3x=nπ+π/4=(4nπ+π)/4=(4n+1)π/4

x=(4nπ+1)π/12,n is an integer.

cot 3x=2

tan 3x=1/2

3x=tan^{-1}(1/2)≈26.57°+360n

x≈8.86°+120n

6 0

3 years ago