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4 years ago

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Mathematics

1 answer:

Maru [420]4 years ago

7 0

Area of circle = πr²
Area of circle = π x 12 x 12
Area of circle = 452.4cm² (nearest tenth)

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Complete the equation of the line whose y intercept is (0,6) and slope is 3

m_a_m_a [10]

Y = mx + b
m = slope
b= y intercept

so the equation is y= 3x + 6

6 0

4 years ago

Dave wants to buy a bike for $180. He has $40. Dave mows lawns for $10 per lawn.

LenaWriter [7]

Answer:

180 = 40 + 10x

Step-by-step explanation:

5 0

3 years ago

Suppose that P is the point on the unit circle obtained by rotating the initial ray counterclockwise through 330 degrees. Find t

Flauer [41]

Answer:

Reference angle will be 30°

sin(330°) will be equal to $\frac{-1}{2}$

cos(330°) will be equal to 0.866

Step-by-step explanation:

We have given angle is 330°

As the angle $330^{\circ}$ is in forth quadrant

We know that in forth quadrant the reference angle is given by

Reference angle $=360-angle$

As the angle is 330°

So the reference angle will be $=360-330=30^{\circ}$

Now we have to find the value of

sin(330°) $=sin(2\pi -30)=-sin(30)=\frac{-1}{2}$

And now $cos(330^{\circ})=cos(2\pi -30)=cos30=0.866$

4 0

3 years ago

Find the area of the parallelogram shown below.<br> 5<br> 4<br> square units

alina1380 [7]

Length times width and that will get you an answer

6 0

3 years ago

This is due today i would appreciate it a lot if smn could help me with it :/

Vesnalui [34]

Answer:

Conclusion:

The rate of change of function 1 = 3

The rate of change of function 2 = 5/3

Hence, function 1 has a greater rate of change

The initial Value of function 1 = y = 2

The initial Value of function 2 = y = 3

Hence, function 2 has a greater initial value.

Step-by-step explanation:

Function 1)

Determining rate of change for function 1:

x 1 2 3 4

y 5 8 11 14

Finding the rate of change or slope using the formula

Rate of change = m = [y₂-y₁] / [x₂-x₁]

Taking any two points, let say (1, 5) and (2, 8)

Rate of change = m = [8-5] / [2-1]

= 3/1

= 3

Therefor, the rate of change of function 1 = m = 3

using point-slope form to determine the function equation

y-y₁ = m (x-x₁)

where m is the rate of change or slope

substititng m = 3 and the point (1, 5)

y - 5 = 3(x - 1)

y - 5 = 3x-3

y = 3x-3+5

y = 3x + 2

Thus, equation of function 1 will be:

y = 3x + 2

Determining Initial Value for Function 1:

substituting x = 0 in the equation to determine the initial value

y = 3(0)+2

y = 0+2

y = 2

Therefore, the initial Value of function 1 will be: y = 2

Function 2)

Determining the rate of change for function 2:

Given the function 2

$y\:=\:\frac{5}{3}x+3$

comparing with the slope-intercept form of a linear function

y = mx+b where m is the rate of change

so the rate of change of function 2 = m = 5/3

Determining Initial Value for Function 2:

substituting x = 0 in the equation to determine the initial value

$y\:=\:\frac{5}{3}x+3$

$y\:=\:\frac{5}{3}\left(0\right)+3$

$y = 0+3$

$y = 3$

Therefore, the initial Value of function 2 will be: y = 3

Conclusion:

The rate of change of function 1 = 3

The rate of change of function 2 = 5/3

Hence, function 1 has a greater rate of change

The initial Value of function 1 = y = 2

The initial Value of function 2 = y = 3

Hence, function 2 has a greater initial value.

8 0

3 years ago