The solution to the problem is as follows:
The quotient rule is ( f'(x)g(x)-f(x)g'(x) )/ (g(x))^2 {complex written on 1 line I know}
let f(x)=9x +13 and g(x)=2x+4
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f'(x)=9 and g'(x)=2 </span>
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therefore just substitute the equations in. </span>
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y'= 6x - ((9(2x+4)-2(9x+13))/((2x+4)^2))
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I don't know if this is right but I think it is $4500
Answer:
8.55
Step-by-step explanation:
Answer:
Step-by-step explanation:
Remark
Read the following carefully.
There is a beautiful theorem that has to do with the endpoints of two angles sharing the same endpoints.
To be a little clearer, I hope, that makes < BAC = <BDC because both angles have B and C as their endpoints inside the circle. Make sure you understand that statement before moving on.
For this problem <BDC = <CAB = 33 degrees.
That means that ADC = 37 + 33 = 70
Solution
<ADC and CBA are opposite angles.
That means that they add to 180
From the above statement in the Remark section <ADC = 37 + 33 = 70 degrees <ABD + <DBC = <ABC = m + 71
<ABC + ADC = 180
m + 71 + 70 = 180 Combine
m + 141 = 180 Subtract 141 from both sides.
m+141-141= 180 - 141 Combine
m = 39
Answer: m = 39
