All categories

3 years ago

What is this answer?

Mathematics

1 answer:

kvasek [131]3 years ago

3 0

I got S > 2
Because you would multiply both sides by two then subtract by twelve
_

You might be interested in

Ms. Maya was handing out breakfast with Ms. Perez. They were in a race to see who could be most efficient and hand out the most

leonid [27]

Answer:

105-9/2=48: Ms. Maya 105-48=57: Ms. Perez

Step-by-step explanation:

105-9 is 96 divided by 2 is 48 and 105-48 is 57 therefore Ms.Maya handed out 48 breakfasts and Ms.Perez handed out 57 breakfasts

4 0

3 years ago

A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week

Levart [38]

Answer:

99% confidence interval for the population proportion of employed individuals is [0.104 , 0.224].

Step-by-step explanation:

We are given that a simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week.

Of the 250 employed individuals surveyed, 41 responded that they did work at home at least once per week.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

P.Q. = $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of individuals who work at home at least once per week = $\frac{41}{250}$ = 0.164

n = sample of individuals surveyed = 250

<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99 {As the critical value of z at 0.5%

level of significance are -2.5758 & 2.5758}

P(-2.5758 < $\frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < 2.5758) = 0.99

P( $-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < ${\hat p-p}$ < $2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

P( $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ < p < $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ) = 0.99

<em>99% confidence interval for p</em> = [ $\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ , $\hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }$ ]

= [ $0.164-2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } }$ , $0.164+2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } }$ ]

= [0.104 , 0.224]

Therefore, 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is [0.104 , 0.224].

7 0

2 years ago

What is the area of this figure?

vovangra [49]

Witch one are u takin about bc if it's the square the answer is 16 if ur taking about the rain gel the answer is 24

7 0

3 years ago

I need help with questions two and three I do not understand them at all

rosijanka [135]

1. D bc switch the 1/3 into 3/1, then 4 time 3/1 = 12. Basically 4 times 3 =12
2. D

4 0

2 years ago