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Doss [256]
3 years ago
7

What is this answer?

Mathematics
1 answer:
kvasek [131]3 years ago
3 0
I got S > 2
Because you would multiply both sides by two then subtract by twelve
_
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Ms. Maya was handing out breakfast with Ms. Perez. They were in a race to see who could be most efficient and hand out the most
leonid [27]

Answer:

105-9/2=48: Ms. Maya  105-48=57: Ms. Perez

Step-by-step explanation:

105-9 is 96 divided by 2 is 48 and 105-48 is 57 therefore Ms.Maya handed out 48 breakfasts  and Ms.Perez handed out 57 breakfasts

4 0
2 years ago
A simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week
Levart [38]

Answer:

99% confidence interval for the population proportion of employed individuals is [0.104 , 0.224].

Step-by-step explanation:

We are given that a simple random sample of size n=250 individuals who are currently employed is asked if they work at home at least once per week.

Of the 250 employed individuals​ surveyed, 41 responded that they did work at home at least once per week.

Firstly, the pivotal quantity for 99% confidence interval for the population proportion is given by;

                              P.Q. = \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } }  ~ N(0,1)

where, \hat p = sample proportion of individuals who work at home at least once per week = \frac{41}{250} = 0.164

           n = sample of individuals surveyed = 250

<em>Here for constructing 99% confidence interval we have used One-sample z proportion statistics.</em>

So, 99% confidence interval for the population proportion, p is ;

P(-2.5758 < N(0,1) < 2.5758) = 0.99  {As the critical value of z at 0.5%

                                             level of significance are -2.5758 & 2.5758}  

P(-2.5758 < \frac{\hat p-p}{\sqrt{\frac{\hat p(1-\hat p)}{n} } } < 2.5758) = 0.99

P( -2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < {\hat p-p} < 2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

P( \hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } < p < \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } ) = 0.99

<em>99% confidence interval for p</em> = [\hat p-2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } } , \hat p+2.5758 \times {\sqrt{\frac{\hat p(1-\hat p)}{n} } }]

= [ 0.164-2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } } , 0.164+2.5758 \times {\sqrt{\frac{0.164(1-0.164)}{250} } } ]

 = [0.104 , 0.224]

Therefore, 99% confidence interval for the population proportion of employed individuals who work at home at least once per week is [0.104 , 0.224].

7 0
2 years ago
What is the area of this figure?​
vovangra [49]
Witch one are u takin about bc if it's the square the answer is 16 if ur taking about the rain gel the answer is 24
7 0
3 years ago
I need help with questions two and three I do not understand them at all
rosijanka [135]
1. D bc switch the 1/3 into 3/1, then 4 time 3/1 = 12. Basically 4 times 3 =12
2. D
4 0
2 years ago
7^-5 times 7^3 equals what, I need help asap please
djverab [1.8K]
Your answer is 7^(- 2) or \frac{1}{ 7^{2} } or \frac{1}{49}
5 0
2 years ago
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