Answer:
= -4x² + x
Step-by-step explanation:
-3x(8x - 2)
= -24x² + 6x
= -4x² + x
Hello :
<span>–0.5x ≥ 4...(1)
multip by -2 : x </span><span>≤ -8
</span><span>number line represents the solution is :
</span>-∞ـــــــــــــــــــــــــــــــــــــ[8-ــــــــــــــــــــــــــــــــــــ> +∞
Since the four choices have solution, there is no choice that have no solutions. (Correct choice: E)
<h3>What linear equation has no solution?</h3>
Herein we must check each choice to find if a solution exists or not by <em>algebra</em> properties. Now we proceed to check each case:
Choice A
1/(x - 31) = 5
1 = 5 · (x - 31)
1 = 5 · x - 155
5 · x = 156
x = 31.2
Choice B
12 · x - 11 = 0
12 · x = 11
x = 11/12
Choice C
15 - 3 · x = - 8
3 · x = 23
x = 23/3
Choice D
- x + 91 = 0
x = 91
Since the four choices have solution, there is no choice that have no solutions. (Correct choice: E)
<h3>Remark</h3>
The statement presents typing mistakes and is incomplete. Correct form is shown below:
<em>Which equation has no solution?</em>
<em>A. 1/(x- 31) = 5</em>
<em>B. 12 · x - 11 = 0</em>
<em>C. 15 - 3 · x = - 8</em>
<em>D. - x + 91 = 0</em>
<em>E. Neither of all</em>
To learn more on linear functions: brainly.com/question/21107621
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The value of the function h(x + 1) is -x^2 - x + 1
<h3>How to evaluate the function?</h3>
The equation of the function is given as:
h(t) =-t^2 + t + 1
The function is given as:
h(x + 1)
This means that t = x + 1
So, we substitute t = x + 1 in the equation h(t) =-t^2 + t + 1
h(x + 1) =-(x + 1)^2 + (x + 1) + 1
Evaluate the exponent
h(x + 1) =-(x^2 + 2x + 1) + x + 1 + 1
Expand the brackets
h(x + 1) = -x^2 - 2x - 1 + x + 1 + 1
Evaluate the like terms
h(x + 1) = -x^2 - x + 1
Hence, the value of the function h(x + 1) is -x^2 - x + 1
Read more about functions at:
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<u>Complete question</u>
Consider the following function definition, and calculate the value of the function
h(t) = −t2 + t + 1 h(x + 1)