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Charra [1.4K]
2 years ago
10

Write a quadratic function f whose zeros are 3 and 12. f(x) = ?

Mathematics
1 answer:
ololo11 [35]2 years ago
5 0

Answer:

The above equation is a quadratic function whose zeroes are 3 and 12.

Step-by-step explanation:

The general quadratic equation is given by :

ax^2+bx+c=0

It is given that, the zeroes of a quadratic function are 3 and 12. It means they must be factors of it such that,

(x-3)=0\\\\(x-12)=0

So, we can write as :

(x-3)(x-12)=0

Multiplying both factors,

(x-3)(x-12)=0\\\\x^2-12x-3x+36=0\\\\x^2-15x+36=0

So, the above equation is a quadratic function whose zeroes are 3 and 12.

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Answer:

19

Step-by-step explanation:

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2. We are left with q(-17).

2a. We plug -17 into where we x in q(x).

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What's the sum of 2⁄5 and 2⁄4?
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2/5 + 2/4

8/20 = 10/20

8/20 + 10/20 = 18/20

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Your answer is 9/10 or 0.9


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2 years ago
Suppose PV =NRT, where P=8, V=2X, N=2 and R=2X.you are given X=3. Solve for T
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Step-by-step explanation:

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V = 2X = 2(3) = 6

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3. Find PV

PV = P x V

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4. Find NRT

NRT = N x R x T

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The graph of the quadratic function y=-x^2-2x+3 is shown below
Karolina [17]

Answer:

The axis of symmetry is at x=-1

The graph has an x-intercept at (1,0)

The graph has a vertex at (-1,4)

Step-by-step explanation:

we have

y=-x^{2}-2x+3

Statements

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The statement is False

Because, the roots of the quadratic equation are the values of x when the value of y is equal to zero (x-intercepts)

Observing the graph, the roots are at -3 and 1

case 2) The axis of symmetry is at x=-1

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case 3) The graph has an x-intercept at (1,0)

The statement is True

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case 4)  The graph has an y-intercept at (-3,0)

The statement is False

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Observing the graph, the y-intercept is the point (0,3)

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The statement is False

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The point (-1,4) represent the vertex of the parabola, so is a maximum

case 6) The graph has a vertex at (-1,4)

The statement is True

see the procedure case 5)

see the attached figure to better understand the problem

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3 years ago
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