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DiKsa [7]
3 years ago
6

The student body of 85 students wants to

Mathematics
1 answer:
mart [117]3 years ago
4 0
The answer is B !!!!!!!!’nnnnnnsnnaamajsnkanaksnss
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Michael found a jake at the bank he said that he went there every 45 days and Michael says he went every 30 days .when will they
Ahat [919]
They will see each other every 30 days but won't every 15 days
5 0
4 years ago
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What is the value of -2(x + 5)?
Nataly_w [17]

Answer:

5)

1

 

Expand by distributing terms.

-2x-2\times 5−2x−2×5

2

 

Simplify  2\times 52×5  to  1010.

-2x-10−2x−10

3 0
3 years ago
8= 8 + 4x +5x<br><br> can anyone help me with this
dedylja [7]

Answer:

0= x

Step-by-step explanation:

8= 8 + 4x +5x

Combine like terms

8 = 8+9x

Subtract 8 from each side

8-8 =8+9x-8

0 = 9x

Divide by 9

0/9 = 9x/9

0= x

3 0
3 years ago
Find the least common multiple for 6(x+1)^3(x-4)^2 and 10(x+1)^8(x-4)^5
dolphi86 [110]

Answer:

30(x+1)^8 (x-4)^5

Step-by-step explanation

<h3>6(x+1)^{3}(x-4))^{2}=2X3 X (x+1)^3(x-4)^2\\10(x+1)^8(x-4)^5)= 2X5X(x+1)^8 (x-4)^5\\</h3>

In order to find the Least common multiple we write each of the factor only once from each of the expression and for the common expression we take their LCM as maximum of the exponent in  all expressions

as here in the question exponent of (x+1) are 3 and 8 so we take exponent 8

likewise for (x-4) we shall take maximum of 2 and 5 which is 5

so our expression for Least common multiple will be

2X3X5 X (x+1)^8 (x-4)^5

30(x+1)^8 (x-4)^5

7 0
3 years ago
Write a 6-digit number which has 4 ten thousands and 6 tens.​
irga5000 [103]

Answer:

141,161

Step-by-step explanation:

7 0
3 years ago
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