Which of the following lists of ordered pairs is a function?

2 answers:

4 0

A. (1, 2), (0, 3), (1, 4), (6, 5)
It's not a function, becouse:
(1, 2): 1 ⇒ 2 and (1, 4) - 1 ⇒ 4

B. (9, 4), (5, 0), (1, -4), (-2, -6)
It's a function

C. (4, 2), (4, -2), (9, 3), (16, 4)
It's not a function, becouse:
(4, 2): 4 ⇒ 2 and (4, -2): 4 ⇒ -2

D. (9, 4), (5, 0), (5, 3), (-2, -6)
It's not a function, becouse:
(5, 0): 5 ⇒ 0 and (5, 3): 5 ⇒ 3

Zigmanuir [339]3 years ago

4 0

So a function is basically the x values don't repeat with any differnt y values
(x,y)

the first number should never repeat with a differnt y value

A. 1 repeats with2 and 4, not a function
B.. no repeat, it's a function
C. 4 repeats with 2 and -2,not a function
D. 5 repeats with 0 and 3, not a function

answer is B

You might be interested in

Police records in the town of Saratoga show that 17 percent of the drivers stopped for speeding have invalid licenses. If 24 dri

Ymorist [56]

Answer:

Step-by-step explanation:

Given

17 % of the drivers stopped have invalid licenses

n=24 drivers are stopped

using Binomial distribution

$^nC_r(p)^r(q)^{n-r}$

here p=0.17

q=1-0.17=0.83

(a)none will have valid license i.e. r=0

$P(r=0)^{24}C_0(0.17)^0(0.83)^{24}=(0.83)^{24}=0.0114$

(b)Exactly one have invalid license i.e. r=1

$P(r=1)=^{24}C_1(0.17)^1(0.83)^{23}=24\times 0.17\times (0.83)^{23}$

$=0.0561$

(c)At least 2 will have invalid license i.e. $r\geq 2$

$P(r\geq 2)=1-P(r=0)-P(r=1)$

$P(r\geq 2)=1-0.0114-0.0561$

$P(r\geq 2)=0.932$

3 0

3 years ago

The school jazz band consists of 2 male percussionists, 2 female percussionists, 3 male woodwinds, 2 female woodwinds, 4 male br

dusya [7]

Answer:

$\frac{1}{8}$ chance or 12.5% chance

Step-by-step explanation:

2 male percussionists

2 female percussionists

3 male woodwinds

2 female woodwinds

4 male brass players

3 female brass players

We're looking for a female woodwind. Now there is only 2 of them so we get the female woodwinds out of all the jazz band members or $\frac{2}{16}$ or $\frac{1}{8}$ or 12.5% chance.