Ask question

Ask question

All categories

3 years ago

8

Which of the following lists of ordered pairs is a function?

2 answers:

likoan [24]3 years ago

4 0

A. (1, 2), (0, 3), (1, 4), (6, 5)
It's not a function, becouse:
(1, 2): 1 ⇒ 2 and (1, 4) - 1 ⇒ 4

B. (9, 4), (5, 0), (1, -4), (-2, -6)
It's a function

C. (4, 2), (4, -2), (9, 3), (16, 4)
It's not a function, becouse:
(4, 2): 4 ⇒ 2 and (4, -2): 4 ⇒ -2

D. (9, 4), (5, 0), (5, 3), (-2, -6)
It's not a function, becouse:
(5, 0): 5 ⇒ 0 and (5, 3): 5 ⇒ 3

Zigmanuir [339]3 years ago

4 0

So a function is basically the x values don't repeat with any differnt y values
(x,y)

the first number should never repeat with a differnt y value

A. 1 repeats with2 and 4, not a function
B.. no repeat, it's a function
C. 4 repeats with 2 and -2,not a function
D. 5 repeats with 0 and 3, not a function

answer is B

You might be interested in

A is an m×n matrix.Check the true statements below:A. The kernel of a linear transformation is a vector space.B. If the equation

Bess [88]

Answer:

Results are (1) True. (2) False. (3) False. (4) True. (5) True. (6) True.

Step-by-step explanation:

Given A is an $m\times n$ matrix. Let $T :U\to V$ be the corresponding linear transformationover the field F and $\theta$ be identity vector in V. Now if $x\in Ker( T)\implies T(x)=\theta$ .

(1) The kernel of a linear transformation is a vector space : True.

Let $x,y\in Ker( T)$ , then,

$T(x+y)=T(x)+T(y)=\theta+\theta=\theta\impies x+y\in Ker( T)$

hence the kernel is closed under addition.

Let $\lambda\in F, x\in Ker( T)$ , then

$T(\lambda x)=\lambda T(x)=\lambda\times \theta=\theta$

$\lambda x\in Ker(T)$ and thus Ket(T) is closed under multiplication

Finally, fore all vectors $u\in U$ ,

$T(\theta)=T(\theta+(-\theta))=T(\theta)+T(-\theta)=T(\theta)-T(\theta)=\theta$

$\implies \theta\in Ker(T)$

Thus Ker(T) is a subspace.

(2) If the equation Ax=b is consistent, then Col(A) is $\mathbb R^m$ : False

if the equation Ax=b is consistent, then Col(A) must be consistent for all b.

(3) The null space of an mxn matrix is in $\mathbb R^m$

: False

The null space that is dimension of solution space of an m x n matrix is always in $\mathbb R^n$ .

(4) The column space of A is the range of the mapping $x\to Ax$

: True.

(5) Col(A) is the set of all vectors that can be written as Ax for some x. : True.

Here Ax will give a linear combination of column of A as a weights of x.

(6) The null space of A is the solution set of the equation Ax=0.

: True

5 0

3 years ago

Which number is a common factor of 64 and 100?<br><br> A) 4 <br> B) 8 <br> C) 16 <br> D) 20

antiseptic1488 [7]

Answer:

4

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Sammi has 2 1/3 feet of rope. If he cuts the rope into pieces that are each 1/2 foot long, there will be 1/3 foot of rope left o

Stells [14]

Answer:

Step-by-step explanation:

Sammi has 2 1/3 feet of rope.

To write this type of fraction = 2 + 1/3 - The integer 2 in the expression is the amount of feet of rope that was cut.

Thus to know the number of 1/2 foot pieces produced, let this number be x. Thus, we have 1/2 of x pieces = 2

x/2 = 2; x = 2x2 = 4.

Thus, Sanmi has 4 pieces of 1/2 foot long piece each of rope.

4 0

3 years ago

Find the value of a and explain

Irina-Kira [14]

Answer:

D

Step-by-step explanation:

The triangle is an isosceles triangle which means that two sides are the same, A is the same size of the equal side so A is D.

3 0

3 years ago

Read 2 more answers

PLEASE ANSWER THIS ONLY 6-8 RIGHT NOW!

Anika [276]

Answer:

6: compression 7: translation 8: Reflection

4 0

3 years ago