Answer:
701 revolutions
Step-by-step explanation:
Given: Length= 2.5 m
Radius= 1.5 m
Area covered by roller= 16500 m²
Now, finding the Lateral surface area of cylinder to know area covered by roller in one revolution of cylindrical roller.
Remember; Lateral surface area of an object is the measurement of the area of all sides excluding area of base and its top.
Formula; Lateral surface area of cylinder= 
Considering, π= 3.14
⇒ lateral surface area of cylinder= 
⇒ lateral surface area of cylinder= 
∴ Area covered by cylindrical roller in one revolution is 23.55 m²
Next finding total number of revolution to cover 16500 m² area.
Total number of revolution= 
Hence, Cyindrical roller make 701 revolution to cover 16500 m² area.
2t+3n=9 2(2)+3n=9
+5t-3n=5 (the 3n cancel out) 4+3n=9
7t=14 3n=5
t=2 n=5/3 or 1.67
Answer:
x= -3 or 4/3
Step-by-step explanation:
3x²+5x-12 =0
3x²+9x-4x-12=0
3x(x+3) -4(x+3) =0
(3x-4)(x+3)=0
x=-3 or 4/3
As the 2 quadrilaterals are congruent the sides of one quadrilateral are equal to the corresponding sides of the other quadrilateral
Hence,
AB = PQ
RQ = BC
AD = PS
DC = RS
Since terms for both AB and PQ are given we can equate the terms and find m
5m -9 = m + 11
5m -m = 11 + 9
4m = 20
m = 5
Correct answer is D , 5