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ladessa [460]
2 years ago
6

Find the z value such that 39% of the standard normal curve lies between −z and z.

Mathematics
2 answers:
zavuch27 [327]2 years ago
3 0
Use symmetry and find z so that probability is:
(100-39)/2
=61%
=30.5%~0.305
From the z-table:
z=-0.51
Answer: -0.51
zaharov [31]2 years ago
3 0

Answer:

Value of Z =0.51

Step-by-step explanation:

Given that P(-z<0<z) = 0.39

Or P(0<z) = 0.39/2 = 0.195

From standard normal table we find that

0.51 satisfies that

P(0<z<0.51) = 0.195

Hence value of z = 0.51

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Answer:

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Step-by-step explanation:

a) To approximate this distribution we have to calculate the mean and the standard distribution.

The mean is the proportion p=0.85.

The standard deviation can be calculates as:

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To calculate the probability that Jodi scores 78% or less on a 100-question test, we first calculate the z-value:

z=\frac{p-p_0}{\sigma} =\frac{0.78-0.85}{0.04} =-1.75

The probability for this value of z is

P(x

The probability that Jodi scores 78% or lower on a 100-question test is 4%.

b) In this case, the number of questions is 250, so the standard deviation needs to be calculated again:

\sigma=\sqrt{\frac{p(1-p)}{n} }= \sqrt{\frac{0.85*(1-0.85)}{250} }=0.02

To calculate the probability that Jodi scores 78% or less on a 250-question test, we first calculate the z-value:

z=\frac{p-p_0}{\sigma} =\frac{0.78-0.85}{0.02} =-3.5

The probability for this value of z is

P(x

The probability that Jodi scores 78% or lower on a 250-question test is 0.023%.

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2 years ago
On the first visit to the veterinarian's office, Elijah's puppy weighed 19 ounces. On the 2nd visit, the puppy had gained 9 ounc
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Answer:

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Answer:

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Step-by-step explanation:

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