Answer:
If B is between A and C, AB = x, BC = 2x + 2, and AC = 14, find the value of x. Then find AB and BC.
Step-by-step explanation:
AB=x
BC = 2x + 2BC=2x+2
AC =14AC=14
Required
Determine x, AB and BC.
Since B is between A and C;
AB + BC = ACAB+BC=AC
Substitute x for AB; 2x + 2 for BC and 14 for AC
x + 2x + 2 = 14x+2x+2=14
3x + 2 = 143x+2=14
Collect Like Terms
3x = 14 - 23x=14−2
3x = 123x=12 '
x = \frac{12}{3}x=
3
12
x = 4x=4
Substitute 4 for x in
AB = xAB=x
BC = 2x + 2BC=2x+2
AB = 4AB=4
BC = 2(4) + 2BC=2(4)+2
BC = 8 + 2BC=8+2
BC = 10BC=10
Step by step:
x(2)−3x+14
=2x+−3x+14
Combine Like Terms:
=2x+−3x+14
=(2x+−3x)+(14)
=−x+14
Answer:
=−x+14
For some reason I could only find one... sorry!
Hope I could help thou! :)

The unknown b is stuck in the exponent position.
We can can fix that by using logarithms.
Log is the inverse operation of the exponential.
We'll take log of each side.
Log of what base tho?
Well, the base of our exponential is e,
so we'll take log base e of each side.

We'll apply one of our log rules next:

This allows us to take the exponent out of the log,

Another thing to remember about logs:
When the base of the log matches the inside of the log,
then the whole thing is simply 1,



So our equation simplifies to this,

As a final step, divide both sides by 3,

k, hope that helps!
Answer:
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Step-by-step explanation:
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