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4 years ago

PLEASE HELP!!! BRAINLIEST!!!

Mathematics

1 answer:

KATRIN_1 [288]4 years ago

7 0

Answer:

6x ≤ 40

x ≤ 6

Step-by-step explanation:

Assuming you mean that every time you make a product, $6 dollars comes off your limit:

6x ≤ 40

x ≤ 6.666666...

Because you cant make a fraction of a product:

x ≤ 6

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2<br> Write the ratio 2kg: 500g in its simplest form

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Answer:

1kg:250g

Step-by-step explanation:

2kg:500g

dividing both sides by 2, we get

1kg:250g

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3 years ago

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Answer:

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Step-by-step explanation:

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4 years ago

Match each spherical volume to the largest cross sectional area of that sphere

zlopas [31]

Answer:

Part 1) $324\pi\ units^{2}$ ------> $7,776\pi\ units^{3}$

Part 2) $36\pi\ units^{2}$ ------> $288\pi\ units^{3}$

Part 3) $81\pi\ units^{2}$ ------> $972\pi\ units^{3}$

Part 4) $144\pi\ units^{2}$ ------> $2,304\pi\ units^{3}$

Step-by-step explanation:

we know that

The largest cross sectional area of that sphere is equal to the area of a circle with the same radius of the sphere

Part 1) we have

$A=324\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$324\pi=\pi r^{2}$

Solve for r

$r^{2}=324$

$r=18\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=18\ units$

substitute

$V=\frac{4}{3}\pi (18)^{3}$

$V=7,776\pi\ units^{3}$

Part 2) we have

$A=36\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$36\pi=\pi r^{2}$

Solve for r

$r^{2}=36$

$r=6\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=6\ units$

substitute

$V=\frac{4}{3}\pi (6)^{3}$

$V=288\pi\ units^{3}$

Part 3) we have

$A=81\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$81\pi=\pi r^{2}$

Solve for r

$r^{2}=81$

$r=9\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=9\ units$

substitute

$V=\frac{4}{3}\pi (9)^{3}$

$V=972\pi\ units^{3}$

Part 4) we have

$A=144\pi\ units^{2}$

The area of the circle is equal to

$A=\pi r^{2}$

$144\pi=\pi r^{2}$

Solve for r

$r^{2}=144$

$r=12\ units$

Find the volume of the sphere

The volume of the sphere is

$V=\frac{4}{3}\pi r^{3}$

For $r=12\ units$

substitute

$V=\frac{4}{3}\pi (12)^{3}$

$V=2,304\pi\ units^{3}$

5 0

3 years ago

Read 2 more answers

SUMAR

charle [14.2K]

Answer:

56 + 23 + (-5)

you want to expand the bracket first

23 + (-5)

23-5 = 18

56 + 18 = 74

a) 74

6 + 24 + (-2)

24 - 2= 22

6 + 22 = 28

b) 28

3 + 7 + (-42)

7 - 42 = -35

3 - 35 = -32

c)-32

( 8 + 1 ) + (-3)

+(-3) = -3

9 - 3 = 6

d)6

( 7 + 10 ) + ( 3 + 1 )

17 + 4 = 21

e)21

59 + 2+ (-6)

2+(-6) = 2-6 = -4

59-4

f)55

41 + ( -89)

41 - 89

= - 48

g)-48

( - 13) + 33

-13+33

= 20

h) 20

8 0

3 years ago