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Aleksandr-060686 [28]

2 years ago

14

Kiran has 2 & 3/4 pounds of flour. When he divides the flour into equal-sized bags, he fills 4 & 1/8 bags. How many poun

ds fit in each bag?

1 answer:

Firlakuza [10]2 years ago

3 0

Answer:

The number of pounds that will fit in each bag is 2/3 pounds of flour

Step-by-step explanation:

Here, we want to know the amount of pounds that will fit in each bag

What we have to do here is to divide the total number of pounds of flour, by the number of bags filled

We have this as;

2 3/4 divided by 4 1/8

This is;

11/4 divided by 33/8

= 11/4 * 8/33 = 2/3 pounds

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Which equations have infinitely many solutions?

igomit [66]

Answer:

4(x - 1) = 4x - 4

3x + 6 = 3(x + 2)

Step-by-step explanation:

The first equation is

$5x - 1 = 5x + 1$

We simplify to get;

$- 1 = 1$

This is not true, therefore this equation has no solution.

The second equation is

$3x - 1 = 1 - 3x$

Combine like terms:

$3x + 3x = 1 + 1$

$6x = 2$

$x = \frac{1}{3}$

This has a unique solution.

The 3rd equation is

$7x - 2 = 2x - 7$

Group similar terms:

$7x - 2x = 7 + 2 \\ 5x = 9 \\ x = \frac{9}{5}$

The 4th equation is :

$4(x - 1) = 4x - 4$

$4x - 4= 4x - 4 \\ x = x$

This is always true. The equation has infinite solution.

The 5th equation is:

$3x + 6 = 3(x + 2) \\ 3x + 6 = 3x + 6 \\ x = x$

This also has infinite solution

The 6th equation is

$3(x - 4) = 4(x - 3) \\ 3x - 12 = 4x - 12 \\ 3x - 4x = - 12 + 12 \\ x = 0$

It has a unique solution.

8 0

3 years ago

×^2+4x-5/×^2+7x+1<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%7Bx%7D%5E%7B2%7D%20%2B%204x%20%2B%20-%205%20%7D%20%20%20

Serjik [45]

(4x2 – 4x – 7)(x + 3)

(4x2 – 4x – 7)(x) + (4x2 – 4x – 7)(3)

4x2(x) – 4x(x) – 7(x) + 4x2(3) – 4x(3) – 7(3)

4x3 – 4x2 – 7x + 12x2 – 12x – 21

4x3 – 4x2 + 12x2 – 7x – 12x – 21

4x3 + 8x2 – 19x – 21

6 0

3 years ago

Figure ABCD is a parallelogram. If ABCD is also a rhombus, what must be the value of x? 13 15 18 23

nevsk [136]

Answer: First option 13

Solution

If ABCD is a rhombus, the diagonals must be perpendicular, then the angle (5x+25)° must be a right angle (90°):

(5x+25)°=90°

5x+25=90

Solving for x: Subtracting 25 both sides of the equation:

5x+25-25=90-25

Subtracting:

5x=65

Dividing both sides of the equation by 5:

5x/5=65/5

Dividing:

x=13

Answer: The value of x must be 13

6 0

3 years ago

Read 2 more answers

Suppose that we roll a red and a black die. Let a = "the black die shows a 2 or a 5", b = "the sum of the two dice is at least 7

Novosadov [1.4K]

Answer: No, A and B are not independent events.

∵ it does not satisfy the rule of probability for independent events i.e.

P(A∩B)=P(A).P(B)

Explanation:

Let A be the event that the black dice shows 2 or 5

Let B be the event that the sum of two dice is atleast 7

Sample space of A={ $(R_1,B_2)(R_2,B_2)(R_3,B_2)(R_4,B_2)$ ( $(R_5,B_2),(R_6,B_2),(R_1,B_5),(R_2,B_5),(R_3,B_5),(R_4,B_5),(R_5,B_5),(R_6,B_5)$ }

Sample space of B= { $(R_1,B_6),(R_2,B_5),(R_2,B_6),(R_3,B_4),(R_3,B_5),(R_3,B_6),$ , $(R_4,B_3),(R_4,B_4),(R_4,B_5),(R_4,B_6),(R_5,B_2),(R_5,B_3),(R_5,B_4),(R_5,B_5)$ , $(R_5,B_6),(R_6,B_2),(R_6,B_3),(R_6,B_4),(R_6,B_5),(R_6,B_5)$ }

P(A)= $\frac{\text{No.of favourable outcomes}}{\text{Total no.of observation}}$

⇒P(A)= $\frac{12}{36}$

⇒P(A)= $\frac{1}{3}$

Similarly,

P(B)= $\frac{20}{36}$

⇒ P(B) = $\frac{5}{9}$

Now for Sample Space of (A∩B)= { $(R_5,B_2)(R_6,B_2)(R_2,B_5)(R_3,B_5)(R_4,B_5)(R_5,B_5)(R_6,B_5)$ }

So, P(A∩B)= $\frac{7}{36}$

Now we apply the formula,

P(A).P(B)=P(A∩B)

$\frac{1}{3}$ × $\frac{5}{9}$ ≠ $\frac{7}{36}$

$\frac{5}{27}$ ≠ $\frac{7}{36}$

∴ The events A and B are not independent events.

3 0

2 years ago

Find the area of the rhombus

bogdanovich [222]

Answer:

65

Step-by-step explanation:

A=(D1XD2)/2

10(13)=130

130/2=65

6 0

2 years ago