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tester [92]
3 years ago
12

Find the value of 3a²-4ab-26² when A= -1 and b-4

Mathematics
1 answer:
nata0808 [166]3 years ago
4 0

Answer:

-657

Step-by-step explanation:

a= -1\\b= 4\\

Substituting the value of a and b

3a^{2}-4ab-26^{2}  \\3(-1)^{2} -4(-1)(4)-676\\3-4(-4)-676\\3+16-676\\19-676\\-657

The value of    3a²-4ab-26²  is -657

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4 0
3 years ago
Which two numbers on the number line have an absolute value of 1.75? Select the location of both numbers on the number line
hram777 [196]

Solution

             To    find   Which two numbers on the number line have  sn  

            absolute value of 1.75  .

            Absolute   value   means    " how  far   a  number    is   from  

            zero "  .

           "1.75"    is    1.75   away   from   zero  .

           and  " -1.75"   is  also   1.75    away   from  zero  .

          i.e

               |  0  - 1.75 |   =   1.75

              |  1.75 - 0 |  =  1.75  

           So ,  the  absolute   value  of   "1.75"    is  1.75  

          similarly  , absolute  value  of  "1.75"   is   1.75  .

          Hence  , the  two  numbers   are   -1.75  and  1.75  .

                 

           

8 0
3 years ago
Read 2 more answers
-4r-8(r-6)=7(5r-1)+8
KATRIN_1 [288]

Answer:

r = 1

Step-by-step explanation:

In this question, we have to solve for the vallue of "r". We will use the distributive property shown below to ease our process.

Distributive Property:

a(b+c) = ab + ac

Now, lets solve this:

-4r-8(r-6)=7(5r-1)+8\\-4r-8r+48=35r-7+8\\-12r+48=35r+1\\48-1=35r+12r\\47=47r\\r=\frac{47}{47}\\r=1

As we have seen the value of r is "1"

6 0
3 years ago
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