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denis-greek [22]
3 years ago
10

(15, 31) is rotated 90 ° counterclockwise which coordinates gives me

Mathematics
1 answer:
dezoksy [38]3 years ago
4 0

Answer:

(-31,15)

Step-by-step explanation:

Rotating 90 degrees clockwise is very simple:

(a,b) 90 degrees= (-b,a)

Very simple.

Just switch sides and add negative to the first term.

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How many solutions does the nonlinear system of equations graphed below have?
Ostrovityanka [42]

Answer:

Option (A)

Step-by-step explanation:

Solution of two functions represented by the graph are the common points or point of intersection of the graphs.

From the graph attached,

Parabola and ellipse are intersecting each other at four points.

Therefore, solutions of the given non linear functions will be FOUR.

Option (A) will be the correct option.

4 0
3 years ago
ms.kirk drove 164 miles in the morning and 219 miles in the afternoon.estimate the total number of miles she drove that day.
Licemer1 [7]
164+219=383 is exact for estimate round 164 to 165 or 160 and 219 to 220 so
165+220=385 or 160+220=380
3 0
3 years ago
Read 2 more answers
((HELP, ASAP! PLEASE EXPLAIN CLEARLY!))
FinnZ [79.3K]
A. 8/$12=21/$x then cross multiply.
B. 1/$1.5
3 0
3 years ago
Jack made 9 identical bags using 5 yards of fabric. How much fabric did Jack use for each bag? Solve on paper and check your wor
meriva

Answer: 5/9 yards

Step-by-step explanation:

From the question, we are informed that Jack made 9 identical bags using 5 yards of fabric.

To calculate the amount of fabric that Jack use for each bag, we have to divide 5 by 9. Thus will be:

= 5 / 9

Therefore, it means that Jack used 5/9 yards for each bag

5 0
3 years ago
Help me solve this please
damaskus [11]

1) A quadratic will have no real roots when its discriminant is negative


0 = ax^2 + bx + c = x^2 + 2k x + (4k-3)


d = b^2 - 4ac =  (2k)^2 - 4(1)(4k-3) = 4k^2 - 16k + 12 < 0


Dividing by 4,


k^2 - 4 k + 3 < 0 \quad\checkmark


We have a positive coefficient on k^2 so this parabola is a CUP (concave up positive) so has a minimum at the vertex. If the vertex y value is less than zero, the inequality will be true in the range between the zeros.


(k-3)(k-1)


That's true for


1 < k < 3


2) We look for the meet of the line and the parabola:


2x + k + 2 = 2x^2 + (k+2)x + 8


0 = 2x^2 + kx + (6-k)


For two intersections we need a positive discriminant:


k^2 - 4(6-k)(2) > 0


k^2 + 8k - 48 > 0


(k+12)(k-4) > 0


That's means two negative or two positive, so


k < 12 or k > 4


6 0
3 years ago
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