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Alecsey [184]
3 years ago
12

Given two functions f(x)=2x+4 and g(x)=−1/5x−3 , what is the function rule for (f+g)(x) ?

Mathematics
1 answer:
Angelina_Jolie [31]3 years ago
5 0

The definition is pretty simple:

(f+g)(x) = f(x)+g(x)

So, we only have to sum the expressions:

f(x)+g(x) = 2x+4 - \dfrac{1}{5}x-3 = \dfrac{9}{5}x+1

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lutik1710 [3]
Neagative six plus r is less than or equal to negative three point five
5 0
3 years ago
20 points help w part b
Hatshy [7]

Answer:

8:07 am

Step-by-step explanation:

It takes 9 minutes to walk from his house to the bus station.  It then takes 92 minutes for the bus to travel from Birmingham to Coventry.  After arriving, he takes 12 minutes to reach his workplace.  This takes a total of 113 minutes.

9 + 92 + 12 = 113

Convert 113 minutes to hours and minutes.

113 - 60 = 53

1 hr and 53 min

He has to be at work by 10.  Subtract the time it takes to get to his work by the time he has to get there.

10 - 1 hr = 9

9 - 53 min = 8:07

The latest time he can leave is 8:07.

3 0
3 years ago
Ben wanted to run with his dad during a race. His dad was running a marathon, which has a distance of 26.2 miles. Ben's goal was
Aneli [31]
The answer in is 4.4 bc 1/3 of 13.1(which is half of the total distance) is 4.4
6 0
3 years ago
You hit a golf ball 90 yards. It travels three-fourths of the distance to the hole. Write an equation you can use to find the di
artcher [175]

Answer:

90=3/4 + d

Explanation :

Where:

90 represents the yard

3/4 represents distance travelled by ball

d represents distance from tee to the hole.

Hence:

90=3/4 + d

7 0
3 years ago
Read 2 more answers
CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte
rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt

By definition of absolute value,

|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)

Over this particular integration interval,

• sin(<em>t</em> ) ≥ 0 for 1 ≤ <em>t</em> < <em>π</em>, and

• sin(<em>t</em> ) < 0 for <em>π</em> < <em>t</em> ≤ 5

so you end up splitting the integral at <em>t</em> = <em>π</em> as

\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt

Now compute the distance:

\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5

\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))

\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82

making B the correct answer.

7 0
2 years ago
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