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2 years ago

14

Seamus has a truck of chairs and tables for a party. There are 8 times as many chairs as tables, for a total of 56 chairs in the

truck. How many tables are in the truck?

1 answer:

DIA [1.3K]2 years ago

3 0

Answer:

7

Step-by-step explanation:

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(Distribute , then simplify the remaining expression. Final answer must be in standard form) Please help !!

Sergeu [11.5K]

Problem 22
$4x^2(2x^2+x-5) - x(x^3+5x^2-3) + 17$
$4x^2(2x^2)+4x^2(x)+4x^2(-5) - x(x^3)-x(5x^2)-x(-3) + 17$
$8x^4+4x^3-20x^2 - x^4-5x^3+3x + 17$
$7x^4-x^3-20x^2+3x + 17$

So the final simplified answer to problem 22 is
$7x^4-x^3-20x^2+3x + 17$

--------------------------------

Problem 23
$-2x(x^3-6x^2+6)+4x^3-(5x^4+10x)$
$-2x(x^3)-2x(-6x^2)-2x(6)+4x^3-(5x^4)-(10x)$
$-2x^4+12x^3-12x+4x^3-5x^4-10x$
$-7x^4+16x^3-22x$

So problem 23 simplifies to
$-7x^4+16x^3-22x$

---------------------------------------------------------

Problem 24
$4b[2a^2-5(3ab-2b^2)]+29ab^2$
$4b[2a^2-5(3ab)-5(-2b^2)]+29ab^2$
$4b[2a^2-15ab+10b^2]+29ab^2$
$4b[2a^2]+4b[-15ab]+4b[10b^2]+29ab^2$
$8a^2b-60ab^2+40b^3+29ab^2$
$8a^2b-31ab^2+40b^3$

So problem 24 simplifies to
$8a^2b-31ab^2+40b^3$

-------------------------------------------------

Problem 25
$2y(6x-4x^2y)+13x^2y^2-6$
$2y(6x)+2y(-4x^2y)+13x^2y^2-6$
$12xy-8x^2y^2+13x^2y^2-6$
$12xy+5x^2y^2-6$

The final answer for problem 25 is
$12xy+5x^2y^2-6$

8 0

3 years ago

Explain 2 3\4 divided by 1\8

Helen [10]

I hope this helps you

8 0

2 years ago

Read 2 more answers

What is the product? 4 • (–5)

AysviL [449]

Answer:

4×(-5)=-20

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Jack is car salesman who works strictly on commision. For every car he sells, he earns 2% commision. Cars sell for $35,000 each.

Dafna11 [192]

He earns 2% commission for every car...and each car sells for 35,000....
so for every car, he earns (0.02(35000) = $ 700

700c = 5000
c = 5000/700
c = 7.14....so he would basically have to sell 8 cars because 7 cars wouldnt quite be enough

5 0

2 years ago

Solve the system using elimination

Pie

Answer:

(x, y) = (3, 1)

Step-by-step explanation:

given the 2 equations

2x + 3y = 9 → (1)

x + 5y = 8 → (2)

multiplying (2) by - 2 then adding to (1) will eliminate the term in x

multiply (2) by - 2

- 2x - 10y = - 16 → (3)

add 1(1) and (3) term by term

(2x - 2x) + (3y - 10y) = (9 - 16)

- 7y = - 7 ( divide both sides by - 7 )

y = 1

Substitute y = 1 in either (1) or (2) and solve for x

(1) : 2x + 3 = 9 ( subtract 3 from both sides )

2x = 6 ( divide both sides by 2 )

x = 3

Solution is (3, 1 )

5 0

3 years ago