We're going to be using combination since this question is asking how many different combinations of 10 people can be selected from a set of 23.
We would only use permutation if the order of the people in the committee mattered, which it seems it doesn't.
Formula for combination:
Where 
represents the number of objects/people in the set and 
represents the number of objects/people being chosen from the set
There are 23 people in the set and 10 people being chosen from the set
Usually I would prefer solving such fractions by hand instead of a calculator, but factorials can result in large numbers and there is too much multiplication. Using a calculator, we get
Thus, there are 1,144,066 different 10 person committees that can be selected from a pool of 23 people. Let me know if you need any clarifications, thanks!
~ Padoru
Divide 4 by 12, which equals approximately 0.33333, then multiply that to 180, which gives us 60. So she sold 180 ears of corn for $60.
Answer:
39 in.
Step-by-step explanation:
As it's a regular hexagon all sides are congruent.
Therefore
7x + 4 = 8x - 1
4 + 1 = 8x - 7x
x = 5.
So the required length is 7(5) + 4 = 39 in.
Answer:
c=2
Step-by-step explanation:
8-4=4
4÷2=2
c=2
brainliest plz?
Answer:
No.
Step-by-step explanation:
Well, is the points (1, -9) does satisfy the equation y = 3x - 6. Then, substituting the values of x, and, y, into the equation y = 3x - 6, we should get a true equation.
y = 3x - 6
-9 = 3 * 1 - 6
-9 = 3 - 6
-9 = -3.
So, the points (1, -9) does not satisfy the equation y = 3x - 6.
