Question

A rectangle has a height of c^3+6c^2+2c and a width of c^2+1

Answer 1

Answer:

$A = c^5+6c^4+3c^3+6c^2+2c$

Step-by-step explanation:

The dimensions of a rectangle are length and breadth/width

Here we are given height . Assuming it to be one of the side of the rectangle , we will do the further calculation

Hence one side is

side 1 = $c^2+1$

And the other side is

Side 2 = $c^3+6c^2+2c$

The area of rectangle = side 1 x side 2

$A= (c^2+1) \times (c^3+6c^2+2c)$

Distributing parenthesis

$=c^2c^3+c^2\cdot \:6c^2+c^2\cdot \:2c+1\cdot \:c^3+1\cdot \:6c^2+1\cdot \:2c$

$=c^3c^2+6c^2c^2+2c^2c+1\cdot \:c^3+1\cdot \:6c^2+1\cdot \:2c$

$=c^5+6c^4+2c^3+c^3+6c^2+2c$

adding similar terms

$c^5+6c^4+3c^3+6c^2+2c$

Hence Area is given by the above polynomial