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Anni [7]
3 years ago
9

A red blood cell placed in a hypertonic solution will shrink in a process called crenation. A red blood cell placed in a hypoton

ic solution will swell and potentially burst in a process called hemolysis. To prevent crenation or hemolysis, a cell must be placed in an isotonic solution such as 0.9% (m/v) NaCl or 5.0% (m/v) glucose. This does not mean that a cell has a 5.0% (m/v) glucose concentration; it just means that 5.0% (m/v) glucose will exert the same osmotic pressure as the solution inside the cell, which contains several different solutes. A red blood cell is placed into each of the following solutions. Indicate whether crenation, hemolysis, or neither will occur. Solution A: 3.21% (m/v) NaCl Solution B: 1.65% (m/v) glucose Solution C: distilled H2O Solution D: 6.97% (m/v) glucose Solution E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl Drag each solution to the appropriate bin.
Biology
2 answers:
Gre4nikov [31]3 years ago
8 0

Answer:

Explanation:

Solution A: 3.21% (m/v) NaCl - Crenation Solution

Solution B: 1.65% (m/v) glucose - Hemolysis Solution

Solution C: distilled H2O - Hemolysis Solution

Solution D: 6.97% (m/v) glucose - Crenation Solution

Solution E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl – Crenation solution

Zolol [24]3 years ago
5 0

The correct answer is:


A: 3.21% (m/v) NaCl Solution will cause crenation because it is hypertonic solution (more solutes)  

B: 1.65% (m/v) glucose Solution will cause hemolysis because it is hypotonic solution


C: distilled H2O Solution will cause hemolysis because it is hypotonic solution


D: 6.97% (m/v) glucose Solution will cause crenation because it is hypertonic solution (more solutes)


E: 5.0% (m/v) glucose and 0.9%(m/v) NaCl will cause neither crenation or hemolysis because it is isotonic solution.



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