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Norma-Jean [14]
3 years ago
10

What is the value of x? 7.2/8.4 = x/36.1

Mathematics
1 answer:
Naily [24]3 years ago
5 0

Answer:

30.94

Step-by-step explanation:

you need to bring 36.1 on the other side by multiplying 7.2/8.4 by 36.1

this equals 30.94

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The price of products may increase due to inflation and decrease due to depreciation. Marco is studying the change in the price
inn [45]

Answer:

Product A has a greater percentage change in price.

Step-by-step explanation:

Part A:

The price f product A, f (<em>x</em>) after <em>x</em> years is given by: 

 f(x) = 0.69\cdot(1.03)^{x}

After <em>x</em> = 0 years, the price of product A is:

f(0) = 0.69\cdot(1.03)^{0}=0.69

After <em>x</em> = 1 years, the price of product A is:

f(1) = 0.69\cdot(1.03)^{1}=0.69\cdot (1+0.03)=0.69\cdot (1+3\%)

After 1 year, the price of product A is 3% times more than the original price.

This means that after one year, the new price is 103% of the original price, which means the price product A is increasing by 3%.

Again after <em>x</em> = 2 years, the price of product A is:

f(2) = 0.69\cdot(1.03)^{2}=[0.69\cdot (1+3\%)]\times (1.03)

This implies that after 2 years, the price of product A is 103% of the price after year 1.

This implies that the price of product A is 3% more than the previous year.

Thus, the price of product A is increasing each year by 3%.

Part B:

The data for Product B is as follows:

Time (t)          Price [f (t)]

   1                   10,100

   2                   10,201

   3                 10,303.01

   4                 10,406.04

Product B is clearly increasing in price.

Consider the changes in price of Product B in the following intervals of years:

  • Year 1 - Year 2:

Price in year 1 = $10,100

Price in Year 2 = $10,201

Compute the increase percentage as follows:

\text{Increase}\%=\frac{10201-10100}{10100}=0.01=1\%

  • Year 2 - Year 3:

Price in Year 2 = $10,201

Price in year 3 = $10,303.01

Compute the increase percentage as follows:

\text{Increase}\%=\frac{10303.01-10201}{10201}=0.01=1\%

  • Year 3 - Year 4

Price in year 3 = $10,303.01

Price in Year 4 = $10,406.04

Compute the increase percentage as follows:

\text{Increase}\%=\frac{10,406.04-10303.01}{10303.01}=0.09999\approx 0.01=1\%

It is quite clear that the price of product B increases by 1% each year.

Thus, Product A has a greater percentage change in price.

3 0
3 years ago
Last​ summer, Karl went to the beach every 5 days. Antonia went to the beach every 33 days. How often did they see each other at
vfiekz [6]

Asuming they started summer at the same time. The logical answer will be none, because it will take at least 165 days for the lcd(5) to overlap and there is not 165 days in a summer.

so it will be a rate of 1 for every 5 times Antonia went to the beach.

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Whos your favorite character from Miraculous Ladybug?! mines Alya and of course cat noir he kinda cute
ivanzaharov [21]

Answer:

CAT NOIR

He's cool and my cousin's fav characters LOL

Step-by-step explanation:

um, he's cool i guess?

8 0
3 years ago
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What's the first step of solving -x^2-4x+16=0 ??? NOW!
MaRussiya [10]

Answer:

Step-by-step explanation:

Use the Quadratic Formula.

-x² - 4x + 16 = 0

x = [4±√(4²-4(-1)(16)]/[2(-1)] = [4±√80]/(-2) = [4±4√5]/(-2) = -2±2√5

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3 years ago
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