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skad [1K]
3 years ago
11

Last​ summer, Karl went to the beach every 5 days. Antonia went to the beach every 33 days. How often did they see each other at

the​ beach?
Mathematics
2 answers:
photoshop1234 [79]3 years ago
7 0
Fastrx72k is 100% correct

vfiekz [6]3 years ago
3 0

Asuming they started summer at the same time. The logical answer will be none, because it will take at least 165 days for the lcd(5) to overlap and there is not 165 days in a summer.

so it will be a rate of 1 for every 5 times Antonia went to the beach.

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Mikaela’s friends brought a big box of crackers to the movie theater. 53 crackers are
slamgirl [31]

Answer:

123 crackers

Step-by-step explanation:

If 1/3 of the box contains sesame seed crackers, then, 2/3 of the box contains whole wheat and cheese flavored crackers.

Total number of whole wheat and cheese flavored crackers = 53 + 29 = 82

Let x be the total number of crackers in the box, so we will have the equation

2/3 x= 82

x = 82 ÷ 2/3; we will get

X =82 x 3/2

X = 123 crackers

4 0
3 years ago
Is terry swim three lapse in 2.5 minutes how long would it take her to swim 20 laps at the same rate
beks73 [17]
3 laps in 2.5 minutes

1 lap = 2.5/3  minute

20 laps =   (2.5/3)*20 = 16.67

20 laps ≈ 16.67 minutes 
5 0
3 years ago
The radius of a circular merry-go-round is 3 meters. which measurement is closest to the area of the merry-go-round in square me
djyliett [7]

Answer:

area of the merry go round =πr²

=22/7×3²

=28.28

answer is option D

4 0
2 years ago
The area of a square tile is the same as the area of a rectangle tile that is 18 inches long and 8 inches wide.
allsm [11]

Step-by-step explanation:

Brother Answer is 12 inches

5 0
3 years ago
Given the equation 5x − 4 = –2(3x + 2), solve for the variable. Explain each step and justify your process.
blagie [28]
A.
5x-4=-2(3x+2) \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
5x-4=-2 \times 3x-2 \times 2 \\
5x-4=-6x-4 \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 6x to both sides} \\
11x-4=-4 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{add 4 to both sides} \\
11x=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{divide both sides by 11} \\
x=0

B.
3(2x-4)=5x-1 \\
6x-12=5x-1 \\
\boxed{11x-12=-1} \Leftarrow \hbox{the first mistake} \\
11x=11 \\
\boxed{x=11} \Leftarrow \hbox{the second mistake}

Megan's solution isn't correct.
The first mistake: she subtracted 5x from the right-hand side of the equation, but added 5x to the left-hand side.
The second mistake: she divided the right-hand side of the equation by 11, but didn't divide the left-hand side.

The correct solution:
3(2x-4)=5x-1 \ \ \ \ \ \ \ \ \ \ \ |\hbox{expand the bracket} \\
3 \times 2x+3 \times (-4)=5x-1 \\ 6x-12=5x-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ |\hbox{subtract 5x from both sides} \\
x-12=-1 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  |\hbox{add 12 to both sides} \\
x=11
3 0
3 years ago
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