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Marianna [84]
2 years ago
7

What's the first step of solving -x^2-4x+16=0 ??? NOW!

Mathematics
1 answer:
MaRussiya [10]2 years ago
5 0

Answer:

Step-by-step explanation:

Use the Quadratic Formula.

-x² - 4x + 16 = 0

x = [4±√(4²-4(-1)(16)]/[2(-1)] = [4±√80]/(-2) = [4±4√5]/(-2) = -2±2√5

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What is the vertex of the following function? f(x) = 2(x+8)^2 - 2
netineya [11]

~~~~~~\textit{vertical parabola vertex form} \\\\ y=a(x- h)^2+ k\qquad \begin{cases} \stackrel{vertex}{(h,k)}\\\\ \stackrel{"a"~is~negative}{op ens~\cap}\qquad \stackrel{"a"~is~positive}{op ens~\cup} \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(x)=2(x+8)^2-2\implies f(x)=2[x-(\stackrel{h}{-8})]^2\stackrel{k}{-2}~\hfill \stackrel{vertex}{(-8~~,~~-2)}

4 0
2 years ago
Determine the total number of roots of each polynomial function. f (x) = 3x^4 + 1)^2
bixtya [17]
F=3x^4+1/x is the answer i got. try too use mathpapa.com if you can

4 0
2 years ago
Read 2 more answers
SCCoast, an Internet provider in the Southeast, developed the following frequency distribution on the age of Internet users. Fin
Tomtit [17]

Answer:

Mean: 40.17 years.

Standard deviation: 10.97 years.

Step-by-step explanation:

The frequency distribution is in the attached image.

We can calculate the mean adding the multiplication of midpoints of each class and frequency, and dividing by the sample size.

The midpoints of a class is calculated as the average of the bounds of the class.

Then, the mean can be written as:

E(X)=\dfrac{1}{N}\sum f_iX_i\\\\\\E(X)=\dfrac{1}{60}(3\cdot15+7\cdot25+18\cdot35+20\cdot45+12\cdot 55)=\dfrac{45+175+630+900+660}{60}\\\\\\E(X)=\dfrac{2,410}{60}=40.17

The standard deviation can be calculated as:

s=\sqrt{\dfrac{1}{N-1}\sum f_i(X_i-E(X))^2}\\\\\\s=\sqrt{\dfrac{1}{59}[3(15-40.17)^2+7(25-40.17)^2+18(35-40.17)^2+20(45-40.17)^2+12(55-40.17)^2]}

\\\\\\s=\sqrt{\dfrac{1}{59}( 1,900.59  + 1,610.90  + 481.12  + 466.58  + 2,639.15  )}\\\\\\s=\sqrt{\dfrac{ 7,098.33 }{59}}=\sqrt{120}=10.97

4 0
3 years ago
Please help I’m giving 38 points =w=
VMariaS [17]

Answer:

302^{2} ft

Step-by-step explanation:

14x22=308

7 0
2 years ago
Read 2 more answers
A container contains 12 diesel engines. The company chooses 5 engines at​ random, and will not ship the container if any of the
Rufina [12.5K]

Answer:\frac{^{10}C_5}{^{12}C_5}

Step-by-step explanation:

Given a total of 12 diesel engines

out of which 2 are defective

Company have to choose 5 good engines to ship.

Therefore no of ways in good engines are selected is ^{10}C_5

no of ways in which any 5 engines are selected from a total of 12 engines is

^{12}C_5

Therefore the required probability =\frac{^{10}C_5}{^{12}C_5}

=\frac{7}{22}=0.318

3 0
3 years ago
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