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Marianna [84]
2 years ago
7

What's the first step of solving -x^2-4x+16=0 ??? NOW!

Mathematics
1 answer:
MaRussiya [10]2 years ago
5 0

Answer:

Step-by-step explanation:

Use the Quadratic Formula.

-x² - 4x + 16 = 0

x = [4±√(4²-4(-1)(16)]/[2(-1)] = [4±√80]/(-2) = [4±4√5]/(-2) = -2±2√5

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Rob and Bob together scored 88 points. If Bob scored 54 points, how many points did Rob score?
Jet001 [13]

Answer:

34 points

Step-by-step explanation:

88 minus 54 equals 34.

7 0
3 years ago
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Joe and Linda have the opportunity to purchase a new home. The house in Glen Oaks is currently worth $250,000 but is predicted t
Dmitry [639]

You can work out the percentage change and that would help you work out the rate of appreciation :)

The formula is ((new value - old value)/old value) * 100.

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Therefore the rate of appreciation is 8% p/a.

7 0
3 years ago
4x+32=24<br> show your work
sp2606 [1]

Answer:

x = -2

Step-by-step explanation:

Original equation:

4x + 32 = 24

Subtract 32 from 24

-8

The equation should look like this now:

4x = -8

Divide both sides by 4

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Hope this helps :)

4 0
3 years ago
The length of a parasite in experiment A is 2.5 × 10–3 inch. The length of a parasite in experiment B is 1.25 × 10–4 inch. How m
torisob [31]

We have been given that :-

The length of a parasite in experiment A is 2.5 \times 10^{-3}

The length of a parasite in experiment B is 1.25 \times 10^{-4}

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1.25 \times 10^{-4}= 0.125 \times 10^{-3}

Clearly, the length of parasite in experiment A is greater than the length of parasite in experiment B.

The difference in the length is given by

2.5 \times 10^{-3} -0.125 \times 10^{-4}

=2.375 \times 10^{-3}

Therefore, the length of the parasite in experiment A is =2.375 \times 10^{-3} inches  greater than the length of the parasite in experiment B.

3 0
3 years ago
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Lady bird [3.3K]

Answer:

I think it would be 25 hours spent playing Mario cart

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3 years ago
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