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maria [59]
3 years ago
5

How do the graphs of f (x) = x 2 and g (x)= 3/4 x 2? relate?

Mathematics
2 answers:
Agata [3.3K]3 years ago
8 0

Answer:

g(x) is a horizontal stretch of f(x) by \frac{3}{4} units.

Step-by-step explanation:

The given functions are;

f(x)=x^2

and

g(x)=\frac{3}{4}x^2

The parent function is f(x)=x^2.

The  function g(x)=\frac{3}{4}x^2 is a horizontal stretch of  f(x)=x^2 by \frac{3}{4} units.

SVETLANKA909090 [29]3 years ago
4 0

Answer:

The function g(x) is stretch of 3/4 units in y-direction  of graph f(x).

Step-by-step explanation:

We have given two functions.

f(x) = x² and g(x) = 3/4x²

We have to find relation between them.

We can stretch a graph in y-direction by multiplying it by a constant.

Graph of f(x) is parabola.

g(x) = 3/4(x²)

g(x) = 3/4f(x)

Hence, the function g(x) is stretch of 3/4 units in y-direction  of graph f(x).

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What is the distance points for (2,-2) and (0,-9)
Ksivusya [100]

The distance between two points (2,-2) and (0,-9) is 7.3 units, which is obtained by graphical method and formula method.

Step-by-step explanation:

The given is,

         Two points are (2,-2) and (0,-9)

Step:1

         By graphical method,

         For two points (2,-2) and  (0,-9)

                  First point (2,-2)

                             The values of x=2 and y=-9 noted in the graph

                  Second point (0,-9)

                              The values of x=0 and y=-9 noted in the graph

                  Now join the two points, measure the distance between the two points,

                   Distance between points are 7.3 units.

                                          ( OR )

Step:1

        By formula method,

              Distance =   \sqrt{(x_{2}- x_{2})  ^{2}+ (y_{2}-y_{1})  ^{2}  }

       Where,

               ( 2,-2) are (x_{1},y_{1})

               (0,-9) are (x_{2},y_{2})

       From the values,

                             = \sqrt{(0- 2)  ^{2}+ (-9+2)  ^{2}  }

                            =  \sqrt{(- 2)  ^{2}+ (-7)  ^{2}  }

                            = \sqrt{4+49  }

                            = \sqrt{53}

                            = 7.280

                            ≅ 7.3

            Distance = 7.3

Result:

           The distance between two points (2,-2) and (0,-9) is 7.3 units, which is obtained by graphical method and formula method.

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( you plug in 2 in every point and those are your answers).

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