How do the graphs of f (x) = x 2 and g (x)= 3/4 x 2? relate?
2 answers:
Answer:
is a horizontal stretch of
by
units.
Step-by-step explanation:
The given functions are;
and
The parent function is .
The function is a horizontal stretch of
by
units.
Answer:
The function g(x) is stretch of 3/4 units in y-direction of graph f(x).
Step-by-step explanation:
We have given two functions.
f(x) = x² and g(x) = 3/4x²
We have to find relation between them.
We can stretch a graph in y-direction by multiplying it by a constant.
Graph of f(x) is parabola.
g(x) = 3/4(x²)
g(x) = 3/4f(x)
Hence, the function g(x) is stretch of 3/4 units in y-direction of graph f(x).
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The solution to the above factorization problem is given as f′(x)=4x³−3x²−10x−1. See steps below.
<h3>What are the steps to the above answer?</h3>Step 1 - Take the derivative of both sides
f′(x)=d/dx(x^4−x^3−5x^2−x−6)
Step 2 - Use differentiation rule d/dx(f(x)±g(x))=d/dx(f(x))±d/dx(g(x))
f′(x)=d/dx(x4)−d/dx(x^3)−d/dx(5x^2)−d/dx(x)−d/dx(6)
f′(x)=4x^3−d/dx(x3)−d/dx(5x^2)−d/dx(x)−d/dx(6)
f′(x)=4x^3−3x2−d/dx(5x^2)−d/dx(x)−d/dx(6)
f′(x)=4x^3−3x^2−10x−d/dx(x)−d/dx(6)
f′(x)=4x^3−3x^2−10x−1−dxd(6)
f′(x)=4x^3−3x^2−10x−1−0
Learn more about factorization:
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