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Svetradugi [14.3K]
3 years ago
8

Choose the correct product of (2x + 10)^2

Mathematics
2 answers:
Shalnov [3]3 years ago
6 0
4x to the 2nd power plus 40x plus 100 is your answer 
wlad13 [49]3 years ago
3 0
(2x+10)(2x+10) use FOIL to solve (First, Outer, Inner, Last)
4x^2+20x+20x+100
Combine like terms
4x^2+40x+100
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For what values of does the equation (2 + 1)^2 + 2 = 10 − 6 have two real and equal roots?
Tatiana [17]

Answer:

(2 + 1)^2 + 2 = 10 - 6  

Falso

Step-by-step explanation:

109 / 5000  

El lado izquierdo

11

 no es igual al lado derecho

4

, lo que significa que la declaración dada es falsa.

Falso

3 0
3 years ago
F(x) =
slega [8]

Answer:

Step-by-step explanation:

the graph correspond to the function f :

6 0
3 years ago
Find Mean, Median, mode and range. Round to the nearest tenth.
Zigmanuir [339]

Answer:

Mean =26.2

Median=27

Mode=32

Range=38

Step-by-step explanation:

From the stem and leaf plot, we obtain the original data as:

9,11,12,12,14,17,25,25,27,32,32,32,33,35,41,42,47

The median is middle observation of the array.

Thebefore the median is 27

The mode is the number that occurs most.

The mode is 32.

The range is the highest observation minus the least observation.

The range is 47-9=38

The mean is given by:

\bar x =  \frac{9 + 11 + 12 + 12 + 14 + 17 + 25 + 25 + 27 + 32 + 32 + 32 + 33 + 35 + 41 + 42 + 47}{17}

\bar x =  \frac{446}{17}  = 26.24

7 0
3 years ago
Roadsign cast of shadow that is 4 feet tall at the same time a 6 foot man standing next to the sign cast a shadow of those 2.4 f
Tanzania [10]

Answer:

10 feets

Step-by-step explanation:

Given that:

Road sign shadow (Rs) = 4 feets

Height of man (Hm) = 6

Man shadow (Ms) = 2.4 feets

Height of road sign (Hr) = x

Height of road sign / shadow of road sign = height of man / shadow of man

Hr/Rs = Hm / Ms

x / 4 = 6 / 2.4

Cross multiply :

4*6 = 2.4*x

24 = 2.4x

x = 24 / 2.4

x = 10 feets

Hence, height of road sign = 10 feets

4 0
3 years ago
Select the correct answer.
Snezhnost [94]

Answer:

That would be week 2 and 4 (B). They are both at 12 students attending

8 0
2 years ago
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