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3 years ago

What is the error percentage - 30 items reviewed with 2 errors?

Mathematics

1 answer:

Bad White [126]3 years ago

6 0

Answer:

7.142

Step-by-step explanation:

error=30-28

error=2

%error=error/actual valuex100

%error=2/28*100

%error= 7.142

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Fifty 6th grade students chose to play outside for free time. This is 25% of the 6th grade class. How many total students are th

Elena L [17]

Answer- 200

you need to find what number who’s 25th percent equal 50

7 0

3 years ago

Find the value of x (click photo)

Zolol [24]

Answer:

x = 130 degrees

Step-by-step explanation:

7-sided polygon = 900 degrees

114 + 138 + 127 + 108 + 142 + 141 + x = 900

770 + x = 900

-770 -770

x = 130

Hope this helped! Have a nice day! Plz mark as brainliest!!!

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5 0

3 years ago

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Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.

Sindrei [870]

Answer:

a) $P(X=3) = 0.1$

b) $P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

c) $P(X=4) = 0.3$

d) $P(X=0) = 0.2$

e) $E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

f) $E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

$P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

4 0

3 years ago

How to solve this equation 2+6x=1-x

aleksley [76]

+x on each side. Then -2 on each side. Then divide both sides by 6 and you have your answer

8 0

3 years ago

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Mathematics textbook grade 4

n200080 [17]

Answer:

so what are u trying to say ,,!!!

Step-by-step explanation:

HAVE A NICE DAY

3 0

3 years ago

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