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3 years ago

Mathematics textbook grade 4

Mathematics

2 answers:

n200080 [17]3 years ago

3 0

Answer:

so what are u trying to say ,,!!!

Step-by-step explanation:

HAVE A NICE DAY

aleksklad [387]3 years ago

3 0

Ummm here’s the link for the textbook? Lol

https://www.nelson.com/mathfocus/grade4/parent/tryout.html

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Round 8,624 to the nearest thousand

Shtirlitz [24]

8,624 rounded to the nearest thousand is 9,000

Hope this helps

-AaronWiseIsBae

8 0

3 years ago

Read 2 more answers

Please reference attached image for the problem that requires solving. Thank you so much for taking the time to help.

Lemur [1.5K]

Explanation:

The number of times the 6-sided number cube will be rolled will is

$750$

Let the numbers greater than 4 be represented below as

$E_1$ $\begin{gathered} E_1=\lbrace5,6\rbrace \\ n(E_1)=2 \end{gathered}$

The number of sample space will be

$n(S)=6$

The probability of rolling a number greater than 4 will be calculated below as

$\begin{gathered} Pr(E_1)=\frac{n(E_1)}{n(S)} \\ Pr(E_1)=\frac{2}{6}=\frac{1}{3} \end{gathered}$

Hence,

To calculate the number of times a number greater than 4 will be rolled will be calculated below as

$\begin{gathered} =Pr(E_1)\times750 \\ =\frac{1}{3}\times750 \\ =250times \end{gathered}$

Hence,

The final answer is

$\Rightarrow250\text{ }times$

5 0

1 year ago

What are the potential solutions of log4x+log4(x+6)=2?

lions [1.4K]

The potential solutions of $log_4x+log_4(x+6)=2$ are 2 and -8.

<h3>Properties of Logarithms</h3>

From the properties of logarithms, you can rewrite logarithmic expressions.

The main properties are:

Product Rule for Logarithms - $log_{b}(a*c)=log_{b}a+log_{b}c$
Quotient Rule for Logarithms - $log_{b}(\frac{a}{c} )=log_{b}a-log_{b}c$
Power Rule for Logarithms - $log_{b}(a^c)=c*log_{b}a$

The exercise asks the potential solutions for $log_4x+log_4(x+6)=2$ . In this expression you can apply the Product Rule for Logarithms.

$log_4x+log_4(x+6)=2\\ \\ x*(x+6)=4^2\\ \\ x^2+6x=16\\ \\ x^2+6x-16=0$

Now you should solve the quadratic equation.

Δ= $b^2-4ac=36-4*1*(-16)=36+64=100$ . Thus, x will be $x_{1,\:2}=\frac{-6\pm \:\sqrt{100} }{2\cdot \:1}=\frac{-6\pm \:10}{2}$ . Then:

$x_1=\frac{-6+10}{2}=\frac{4}{2} =2\\ \\ \:x_2=\frac{-6-10}{2}=\frac{-16}{2} =-8$

The potential solutions are 2 and -8.

Read more about the properties of logarithms here:

brainly.com/question/14868849

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2 years ago

Identify the excluded values of this product. Then rewrite the product in simplest form.

lara [203]

$\frac{6 {y}^{2} + 18y - 60 }{3 {y}^{2} - 12y } \times \frac{ {y}^{2} - 16 }{ {y}^{2} + 2y - 8} \\ \\ \frac{ {6y + 30y - 12y - 60}^{2} }{3y(y - 4)} \times \frac{ {(y)}^{2} - ( {4)}^{2} }{ {y}^{2} + 4y - 2y - 8 } \\ \\ \frac{6y(y + 5) - 12(y + 5)}{3y(y - 4)} \times \frac{(y + 4)(y - 4)}{y(y + 4) - 2(y + 4)} \\ \\ \frac{(6y - 12)(y + 5)}{3y(y - 4)} \times \frac{(y + 4)(y - 4)}{(y + 4)(y - 2)} \\ \\ \frac{6(y - 2)(y + 5)}{3y(y - 2)} \\ \\ \frac{2(y + 5)}{y} .$

8 0

2 years ago

Can someone help me please !

elena55 [62]

The reference angle is
pi/3.

At 180 it would be 9pi/3 so going past that is 10pi/3.

7 0

3 years ago