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Hitman42 [59]
3 years ago
13

Mathematics textbook grade 4

Mathematics
2 answers:
n200080 [17]3 years ago
3 0

Answer:

so what are u trying to say ,,!!!

Step-by-step explanation:

HAVE A NICE DAY

aleksklad [387]3 years ago
3 0
Ummm here’s the link for the textbook? Lol

https://www.nelson.com/mathfocus/grade4/parent/tryout.html
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Round 8,624 to the nearest thousand
Shtirlitz [24]

8,624 rounded to the nearest thousand is 9,000

Hope this helps

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3 years ago
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Please reference attached image for the problem that requires solving. Thank you so much for taking the time to help.
Lemur [1.5K]

Explanation:

The number of times the 6-sided number cube will be rolled will is

750

Let the numbers greater than 4 be represented below as

E_1\begin{gathered} E_1=\lbrace5,6\rbrace \\ n(E_1)=2 \end{gathered}

The number of sample space will be

n(S)=6

The probability of rolling a number greater than 4 will be calculated below as

\begin{gathered} Pr(E_1)=\frac{n(E_1)}{n(S)} \\ Pr(E_1)=\frac{2}{6}=\frac{1}{3} \end{gathered}

Hence,

To calculate the number of times a number greater than 4 will be rolled will be calculated below as

\begin{gathered} =Pr(E_1)\times750 \\ =\frac{1}{3}\times750 \\ =250times \end{gathered}

Hence,

The final answer is

\Rightarrow250\text{ }times

5 0
1 year ago
What are the potential solutions of log4x+log4(x+6)=2?
lions [1.4K]

The potential solutions of log_4x+log_4(x+6)=2 are 2 and -8.

<h3>Properties of Logarithms</h3>

From the properties of logarithms, you can rewrite logarithmic expressions.

The main properties are:

  • Product Rule for Logarithms - log_{b}(a*c)=log_{b}a+log_{b}c
  • Quotient Rule for Logarithms - log_{b}(\frac{a}{c} )=log_{b}a-log_{b}c
  • Power Rule for Logarithms - log_{b}(a^c)=c*log_{b}a

The exercise asks the potential solutions for  log_4x+log_4(x+6)=2. In this expression you can apply the Product Rule for Logarithms.

                                  log_4x+log_4(x+6)=2\\ \\ x*(x+6)=4^2\\ \\ x^2+6x=16\\ \\ x^2+6x-16=0

Now you should solve the quadratic equation.

 

 Δ=b^2-4ac=36-4*1*(-16)=36+64=100. Thus, x will be x_{1,\:2}=\frac{-6\pm \:\sqrt{100} }{2\cdot \:1}=\frac{-6\pm \:10}{2}. Then:

x_1=\frac{-6+10}{2}=\frac{4}{2} =2\\ \\ \:x_2=\frac{-6-10}{2}=\frac{-16}{2} =-8

The potential solutions  are 2 and -8.

Read more about the properties of logarithms here:

brainly.com/question/14868849

4 0
2 years ago
Identify the excluded values of this product. Then rewrite the product in simplest form.
lara [203]

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8 0
1 year ago
Can someone help me please !
elena55 [62]
The reference angle is
pi/3.

At 180 it would be 9pi/3 so going past that is 10pi/3.

7 0
3 years ago
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