Answer:
128 men
Step-by-step explanation:
90 × 28 × 8 = M × 18 × 15/2
M = 128
Answer:
m<A=94
Step-by-step explanation:
(2x+10)+(2x+2)=180
4x+12=180
-12 -12
4x=168
/4 /4
x=42
m<A= 2x+10
m<A=2(42)+10
m<A=84+10
m<A=94
Check:
Add m<A and m<B which should equal 180.
m<B=2x+2
m<B=2(42)+2
m<B=84+2
m<B=86
94+86=180
Well the answer is -2y-4 but the different terms in this problem are 4 and 5y and 3y where 5y and 3y are like terms
Using conditional probability, it is found that there is a 0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.
Conditional Probability
In which
- P(B|A) is the probability of event B happening, given that A happened.
is the probability of both A and B happening.
- P(A) is the probability of A happening.
In this problem:
- Event A: Person has the flu.
- Event B: Person got the flu shot.
The percentages associated with getting the flu are:
- 20% of 30%(got the shot).
- 65% of 70%(did not get the shot).
Hence:
![P(A) = 0.2(0.3) + 0.65(0.7) = 0.515](https://tex.z-dn.net/?f=P%28A%29%20%3D%200.2%280.3%29%20%2B%200.65%280.7%29%20%3D%200.515)
The probability of both having the flu and getting the shot is:
![P(A \cap B) = 0.2(0.3) = 0.06](https://tex.z-dn.net/?f=P%28A%20%5Ccap%20B%29%20%3D%200.2%280.3%29%20%3D%200.06)
Hence, the conditional probability is:
![P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.06}{0.515} = 0.1165](https://tex.z-dn.net/?f=P%28B%7CA%29%20%3D%20%5Cfrac%7BP%28A%20%5Ccap%20B%29%7D%7BP%28A%29%7D%20%3D%20%5Cfrac%7B0.06%7D%7B0.515%7D%20%3D%200.1165)
0.1165 = 11.65% probability that a person with the flu is a person who received a flu shot.
To learn more about conditional probability, you can take a look at brainly.com/question/14398287
I think the answer is 9.3, but I’m not sure