Answer:
If the eggs cost $0.80 per egg, then that'll be 9 eggs and for eggs costing $0.30, it would be 4 eggs to make each place cost the same
This problem can be solved by creating a system of equations and then solving that system.
x + y = 90
65x + 70y = 6000
The first equation is created from the combined total of the weight, and the second is created from the number of boxes being carried as well as the total weight of the truck. The variable x represents the number of large boxes, the variable y represents the number of small boxes. We can use substitution to solve the system.
x + y = 90
x = 90 - y
We have x equal to something, we can sub this into the second equation where there is an x.
65x + 70y = 6000
65(90 - y) + 70y = 6000
5850 - 65y + 70y = 6000
5850 + 5y = 6000
5y = 150
y = 30
Lastly, we can take the solution and sub it into the first equation to find x.
x + 30 = 90
x = 60
So, the large boxes weigh 60 pounds and the small boxes weight 30 pounds.
Answer:
1
Step-by-step explanation:
depends if you have a table , to pick the right one always choose a one that pass more through and between the points and the one that is straight
d + q = 35....d = 35 - q
0.10d + 0.25q = 7.25
0.10(35 - q) + 0.25q = 7.25
3.50 - 0.10q + 0.25q = 7.25
-0.10q + 0.25q = 7.25 - 3.50
0.15q = 3.75
q = 3.75/0.15
q = 25
d + q = 35
d + 25 = 35
d = 35 - 25
d = 10
so there are 25 quarters and 10 dimes
Collect like terms
so take it in steps :
1) -4x^3 * x^-8 . rules of powers state that when you are multiplying like terms(both have to do with x) you can add the powers. thus = -4x^-5
2) 2y^-2 * 5y^5 . same rule as above. since -2+5=3. the number before your coefficient (x or y) tells you how many lots of it you have . the answer becomes 2*5y^3 = 10y^3 .
3) since you are now left with x and y s which are not the same number, you can multiply out ---> 10*-4 = -40
---> y^3*x^-5 stays the same as you can not combine y and x
In total you have : -40y^3*x^-5
