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frez [133]
3 years ago
13

7x+6>or equal to -(x-6)

Mathematics
1 answer:
WINSTONCH [101]3 years ago
3 0

Answer:

x≥ 0

Step-by-step explanation:

7x+6 ≥ -(x-6)

Distribute the minus sign

7x+6 ≥ -x+6

Add x to each side

7x+x+6 ≥ -x+x+6

8x+6 ≥ 6

Subtract 6 from each side

8x+6-6 ≥ 6

8x≥ 0

Divide by 8

8x/8≥ 0/8

x≥ 0

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Alex787 [66]
D is the answer i think it is at least

6 0
4 years ago
5&lt;b-3. whats the answer????
9966 [12]

Answer:

5<b-3

Add 3 on both sides

8<b

The variable will always go on the left side of the equation. To flip the equation, you must also flip the less than sign to a greater than sign.

b>8

Hope I helped!

8 0
3 years ago
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angle 0 is in quadrant 1 with sin0 = 2/5. Use the Pythagorean identity, sin^2 0 + cos^2 0 = 1, to calculate the value of cos0 as
Gwar [14]
We know that
sin²x+cos²x=1
so 
clear cos x
cos x=(+/-)√[1-sin²x]

in this problem
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</span>sin o=2/5
cos x=√[1-(2/5)²]----> cos o=√[1-4/25]----> cos o=√[21/25]---> cos o=√21/5

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cos o=√21/5

7 0
3 years ago
Tamara and Clyde got different answers when dividing 2x4 + 7x3 – 18x2 + 11x – 2 by 2x2 – 3x + 1. Analyze their individual work.
lys-0071 [83]

<em>Note: As you may have unintentionally missed to add the different answers, based on which we had to check who solved correctly between Tamara and Clyda's work. </em>

<em>But, I am actually solving the expression and you must note that whoever (between Tamara and Clyda's work) may have got the same answer or match the answer with mine, would be the one who solved correctly.</em>

Answer:

We conclude that whoever (between Tamara and Clyda's work) may have got the answer as x^2+5x-2 after dividing   2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2 by 2x^2\:-\:3x\:+\:1  , would be the one who solved it correctly.

Step-by-step explanation:

Considering the expression

                            2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2

Lets divide the expression by 2x^2\:-\:3x\:+\:1

Solution Steps:

\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}

Factorizing

2x^4+7x^3-18x^2+11x-2:\quad \left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)

\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{2x^2-3x+1}

Factorizing

2x^2-3x+1:\quad \left(2x-1\right)\left(x-1\right)

\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}

\mathrm{Cancel\:}\frac{\left(x-1\right)\left(2x-1\right)\left(x^2+5x-2\right)}{\left(2x-1\right)\left(x-1\right)}:\quad x^2+5x-2

x^2+5x-2

Thus,

\frac{2x^4+7x^3-18x^2+11x-2}{2x^2-3x+1}=x^2+5x-2

Therefore, we conclude that whoever (between Tamara and Clyda's work) may have got the answer as x^2+5x-2 after dividing   2x^4\:+\:7x^3\:-\:18x^2\:+\:11x\:-\:2 by 2x^2\:-\:3x\:+\:1  , would be the one who solved it correctly.

Keywords: expression, division

Learn more about expression division from brainly.com/question/1575482

#learnwithBrainly

3 0
3 years ago
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Radda [10]

Answer: The slope is 3

Step-by-step explanation:

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