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ivann1987 [24]
3 years ago
15

Find the radius of a circle with an area of 615.75 sq kilometers?

Mathematics
1 answer:
Olegator [25]3 years ago
4 0

area = pi x r^2

615.75 = 3.14 x r^2

r^2 = 615.75/3.14 =196.0987 round to 196.1

r = sqrt(196.1) = 14.00357 round to 14

radius = 14 kilometers

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GIVEN BRAINLIEST, 5 STARS, + THANKS
Olin [163]

Answer:

<u>Option B. Side YZ is the same length as side Y'X'.</u>

Step-by-step explanation:

At first the image is for the given question

The true graph is the attached figure.

As shown at the attached figure.

XYZ is reflected across the y-axis and then translated down 6 units to form X'Y'Z'.

So, X' is the image of point X

     Y' is the image of point Y

     Z' is the image of point Z

And ΔXYZ ≅ ΔX'YΔ'Z'

And the corresponding length are congruent.

We will check the options:

A. X has the same measure as X'. ⇒ True

B. Side YZ is the same length as side Y'X'. ⇒ Wrong

Because YZ will be translated to Y'Z'

C. Z has the same measure as Z'. ⇒ True

D. Side XZ is the same length as side X'Z'. ⇒ True

<u>So, The answer is option B. Side YZ is the same length as side Y'X'.</u>

6 0
3 years ago
Which problem can be solved using the equation shown? 2 dollars and 50 cents x minus 2 dollars = 10 dollars and 50 cents
Kisachek [45]

Answer:

Look below.

Step-by-step explanation:

$2.50*-$2.00=10.50

This isn't right so I don't know what you're asking for...

5 0
4 years ago
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1. Which rule describes a translation that is 8 units to the right and 2 units up?
sineoko [7]
3rd one because it makes sense
7 0
3 years ago
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Find the exact length of the curve. 36y2 = (x2 − 4)3, 5 ≤ x ≤ 9, y ≥ 0
IrinaK [193]
We are looking for the length of a curve, also known as the arc length. Before we get to the formula for arc length, it would help if we re-wrote the equation in y = form.

We are given: 36 y^{2} =( x^{2} -4)^3
We divide by 36 and take the root of both sides to obtain: y = \sqrt{ \frac{( x^{2} -4)^3}{36} }

Note that the square root can be written as an exponent of 1/2 and so we can further simplify the above to obtain: y =  \frac{( x^{2} -4)^{3/2}}{6} }=( \frac{1}{6} )(x^{2} -4)^{3/2}}

Let's leave that for the moment and look at the formula for arc length. The formula is L= \int\limits^c_d {ds} where ds is defined differently for equations in rectangular form (which is what we have), polar form or parametric form.

Rectangular form is an equation using x and y where one variable is defined in terms of the other. We have y in terms of x. For this, we define ds as follows: ds= \sqrt{1+( \frac{dy}{dx})^2 } dx

As a note for a function x in terms of y simply switch each dx in the above to dy and vice versa.

As you can see from the formula we need to find dy/dx and square it. Let's do that now.

We can use the chain rule: bring down the 3/2, keep the parenthesis, raise it to the 3/2 - 1 and then take the derivative of what's inside (here x^2-4). More formally, we can let u=x^{2} -4 and then consider the derivative of u^{3/2}du. Either way, we obtain,

\frac{dy}{dx}=( \frac{1}{6})( x^{2} -4)^{1/2}(2x)=( \frac{x}{2})( x^{2} -4)^{1/2}

Looking at the formula for ds you see that dy/dx is squared so let's square the dy/dx we just found.
( \frac{dy}{dx}^2)=( \frac{x^2}{4})( x^{2} -4)= \frac{x^4-4 x^{2} }{4}

This means that in our case:
ds= \sqrt{1+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{4}{4}+\frac{x^4-4 x^{2} }{4}} dx
ds= \sqrt{\frac{x^4-4 x^{2}+4 }{4}} dx
ds= \sqrt{\frac{( x^{2} -2)^2 }{4}} dx
ds=  \frac{x^2-2}{2}dx =( \frac{1}{2} x^{2} -1)dx

Recall, the formula for arc length: L= \int\limits^c_d {ds}
Here, the limits of integration are given by 5 and 9 from the initial problem (the values of x over which we are computing the length of the curve). Putting it all together we have:

L= \int\limits^9_5 { \frac{1}{2} x^{2} -1 } \, dx = (\frac{1}{2}) ( \frac{x^3}{3}) -x evaluated from 9 to 5 (I cannot seem to get the notation here but usually it is a straight line with the 9 up top and the 5 on the bottom -- just like the integral with the 9 and 5 but a straight line instead). This means we plug 9 into the expression and from that subtract what we get when we plug 5 into the expression.

That is, [(\frac{1}{2}) ( \frac{9^3}{3}) -9]-([(\frac{1}{2}) ( \frac{5^3}{3}) -5]=( \frac{9^3}{6}-9)-( \frac{5^3}{6}-5})=\frac{290}{3}


8 0
3 years ago
Please help this is so confusing u can have 25 points if u help me
Elina [12.6K]

Step-by-step explanation:

Share 20pounds in the ratio 2:3

Total ratio=2+3=5

2/5×20=8

20-8=12

Sharing 20pounds in that ratio gives 8pounds:12pounds

Share 15cm in the ratio 1:3

Total ratio=1+4=4

¼×15=3.75

15-3.75=11.25

Sharing 15cm in that ratio gives 3.75:11.25

7 0
3 years ago
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