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Anni [7]
3 years ago
6

What is the first step in solving the quadratic equation x^2=9/16

Mathematics
2 answers:
Firlakuza [10]3 years ago
7 0
The answer is C, I believe.
sdas [7]3 years ago
7 0

Answer:

"Take the square root of both sides of the equation"

A is correct

Step-by-step explanation:

We are given quadratic equation x^2=\dfrac{9}{16}

We need to solve for x. We have to isolate x here.

Here square on x. So, first we get rid of square.

Taking square root both sides to get rid of square.

For example:

a^2=25

\sqrt{a^2}=\pm\sqrt{25}

x^2=\dfrac{9}{16}  to solve for x

Taking square root both sides

\sqrt{x^2}=\pm \sqrt{\dfrac{9}{25}}

x=\pm\dfrac{3}{5}

Hence, "Take the square root of both sides of the equation"

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solve for each please i really need help if u want to help me with my test and i get an a or a b i will give u 500 dollars
Len [333]

Answer:

The relation is not a function

The domain is {1, 2, 3}

The range is {3, 4, 5}

Step-by-step explanation:

A relation of a set of ordered pairs x and y is a function if

  • Every x has only one value of y
  • x appears once in ordered pairs

<u><em>Examples:</em></u>

  • The relation {(1, 2), (-2, 3), (4, 5)} is a function because every x has only one value of y (x = 1 has y = 2, x = -2 has y = 3, x = 4 has y = 5)
  • The relation {(1, 2), (-2, 3), (1, 5)} is not a function because one x has two values of y (x = 1 has values of y = 2 and 5)
  • The domain is the set of values of x
  • The range is the set of values of y

Let us solve the question

∵ The relation = {(1, 3), (2, 3), (3, 4), (2, 5)}

∵ x = 1 has y = 3

∵ x = 2 has y = 3

∵ x = 3 has y = 4

∵ x = 2 has y = 5

→ One x appears twice in the ordered pairs

∵ x = 2 has y = 3 and 5

∴ The relation is not a function because one x has two values of y

∵ The domain is the set of values of x

∴ The domain = {1, 2, 3}

∵ The range is the set of values of y

∴ The range = {3, 4, 5}

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