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Elis [28]
3 years ago
12

30 tens - 3 tens 3 tenths

Mathematics
1 answer:
Lady_Fox [76]3 years ago
4 0
 the expression 30 tens - 3 tens 3 tenths. A number proceeded by "tens" means that the number is multiplied by 10 while "tenths" means that the number is divided by 10. 30*10 - 3*10*3/10 equal to 300 - 9 or 291. 
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Select correct answers multiple choice
Darina [25.2K]
The answer to the question is c

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4 years ago
Find the value of x. 7, 8, and 9 please!
natima [27]

Answer:

7) x= 5, 8) x= 6, 9) x= 7

Step-by-step explanation:

As per the secant theoram, if two secant intersect outside the circle then the product of the exterior secant and total length of each secant are equal.

7) ∴ (x+3)\times 3= (10+2)\times 2

opening parethesis and distributing 3 with x and 3.

⇒ 3x+9=24

subtracting 9 on both side.

⇒ 3x=15

cross multiplying

∴ x= 5.

8) (3+5)\times 5= (x+4)\times 4

Opening parethesis and distributing 4 with x and 4.

⇒ 8\times 5=4x+16

⇒ 40=4x+16

subtracting 16 on both side.

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cross multiplying

∴ x= 6.

9) (x+5)\times 5= (6+4)\times 6

opening parethesis and distributing 5 with x and 5.

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subtracting 25 on both side.

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6 0
3 years ago
Factor x2 + 4x + 4! Please help!
Luden [163]
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5 0
4 years ago
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Solve the following system of equations.
sasho [114]
X is  minus 2
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4 years ago
The University of Texas at Austin has three times as many students enrolledas the University of Miami. The University of Califor
harina [27]

Answer:

University of Texas has 46,500 students, University of California has 34,000 students and University of Miami has 15,500 students.

Step-by-step explanation:

Represent Texas with T, Miami with M and California with C. With the given information, the following equations were obtained.

T = 3 × M

T – 3M = 0 ………………………….(i)

C = 3,000 + 2 × M

C – 2M = 3,000…………………..(ii)

T + C + M = 96,000…………….(iii)

By rearranging, we have:

1T + 0C – 3M = 0 ………………………….(i)

0T + 1C – 2M = 3,000…………………..(ii)

1T + 1C + 1M = 96,000………….…….(iii)

The Augmented Matrix is:

\left[\begin{array}{ccc}1&0&-3\\0&1&-2\\1&1&1\end{array}\right]\left[\begin{array}{ccc}T\\C\\M\end{array}\right] = \left[\begin{array}{ccc}0\\3,000\\96,000\end{array}\right]

Making \left[\begin{array}{ccc}T\\C\\M\end{array}\right] the subject of the formula we have:

\left[\begin{array}{ccc}T\\C\\M\end{array}\right] = \frac{\left[\begin{array}{ccc}0\\3,000\\96,000\end{array}\right]}{\left[\begin{array}{ccc}1&0&-3\\0&1&-2\\1&1&1\end{array}\right]}

Let’s say matrix A = \left[\begin{array}{ccc}1&0&-3\\0&1&-2\\1&1&1\end{array}\right], the inverse of matrix A = \left[\begin{array}{ccc}\frac{1}{2} &-\frac{1}{2} &\frac{1}{2} \\-\frac{1}{3} &\frac{2}{3} &\frac{1}{3} \\-\frac{1}{6} &-\frac{1}{6} &\frac{1}{6} \end{array}\right] is determined by the formula \frac{Adjoint(A)}{determinant(A)}. This can also be computed directly on a scientific calculator.

\left[\begin{array}{ccc}T\\C\\M\end{array}\right] = \left[\begin{array}{ccc}\frac{1}{2} &-\frac{1}{2} &\frac{1}{2} \\-\frac{1}{3} &\frac{2}{3} &\frac{1}{3} \\-\frac{1}{6} &-\frac{1}{6} &\frac{1}{6} \end{array}\right] \left[\begin{array}{ccc}0\\3,000\\96,000\end{array}\right]

= \left[\begin{array}{ccc}46,500\\34,000\\15,500\end{array}\right]

T = 46,500

C = 34,000

M = 15,500

6 0
4 years ago
Read 2 more answers
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