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3 years ago

I need help with #5 please help and I need the work

Mathematics

2 answers:

Nookie1986 [14]3 years ago

7 0

If Paul's height is equal to 69.4 inches, we can plug this value into the equation for h and solve for the length of his tibia bone, t.

h = 2.4t + 32.2 (given)

69.4 = 2.4t + 32.2 (substitute)

37.2 = 2.4t (subtract 32.2 from both sides)

15.5 = t (divide both sides by 2.4)

Since there is a 5 in the hundredths place, we round up to 16.

Answer:

The approximate length of Paul's tibia bone is 16 inches

RUDIKE [14]3 years ago

3 0

Plug in 69.4 for
69.4= 2.4t+ 32.2
-32.2 - 32.2
37.2=2.4t
15.5=t
So, t is approximately 16 inches

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3 years ago

. The mean width of 12 iPads is 5.1 inches. The mean width of 8 Kindles is 4.8 inches. a. What is the total width of the iPads?

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Step-by-step explanation:

Given:

The mean width of 12 I-Pads is 5.1 inches.

The mean width of 8 Kindles is 4.8 inches.

Question asked:

a. What is the total width of the I-Pads?

b. What is the total width of the Kindles?

c. What is the mean width of the 12 I-Pads and 8 Kindles?

Solution:

<u /> $Mean =\frac{Sum\ of\ observations}{Number\ of\ observations}\\ \\ Mean\ width =\frac{Sum\ of\ width\ of\ all \ I-pad}{Number \ of\ I-pad}$

$5.1=\frac{Sum\ of\ width\ of\ all\ I-pad}{12} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all\ I-pad}=5.1\times1 2\\ \\ Sum\ of\ width\ of\ all\ I-pad}= 61.2$

a) Thus, the total width of the I-Pads are 61.2 inches.

$Mean\ width =\frac{Sum\ of\ width\ of\ all\ Kindles}{Number \ of\ Kindles}$

$4.8=\frac{Sum\ of\ width\ of\ all\Kindles}{8} \\ \\ By \ cross\ multiplication\\ \\ Sum\ of\ width\ of\ all \ Kindles=4.8\times8\\ \\ Sum\ of\ width\ of \ all\ Kindles}=38.4$

b) Thus, total width of the Kindles are 38.4 inches.

Combined width of both I-pad and Kindles = 61.2 + 38.4 = 99.6 inches

Combined number of observations = 12 + 8 =20

Combined mean of width of the 12 I-Pads and 8 Kindles = Combined width of both I-pad and Kindles $\div$ Combined number of observations

Combined mean of width of the 12 I-Pads and 8 Kindles = $\frac{99.6}{20} =4.98\ inches$

c) Thus, the mean width of the 12 I-Pads and 8 Kindles is 4.98 inches.

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3 years ago