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Thepotemich [5.8K]
3 years ago
5

I need help with #5 please help and I need the work

Mathematics
2 answers:
Nookie1986 [14]3 years ago
7 0

If Paul's height is equal to 69.4 inches, we can plug this value into the equation for h and solve for the length of his tibia bone, t.

h = 2.4t + 32.2 (given)

69.4 = 2.4t + 32.2 (substitute)

37.2 = 2.4t (subtract 32.2 from both sides)

15.5 = t (divide both sides by 2.4)

Since there is a 5 in the hundredths place, we round up to 16.

Answer:

The approximate length of Paul's tibia bone is 16 inches

RUDIKE [14]3 years ago
3 0
Plug in 69.4 for
69.4= 2.4t+ 32.2
-32.2 - 32.2
37.2=2.4t
15.5=t
So, t is approximately 16 inches
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A geometric series has second term 375 and fifth term 81 . find the sum to infinity of series .
Eduardwww [97]

Answer:  \bold{S_{\infty}=\dfrac{3125}{2}=1562.5}

<u>Step-by-step explanation:</u>

  a₁,  375,  a₃,   a₄,  81

First, let's find the ratio (r). There are three multiple from 375 to 81.

375r^3=81\\\\r^3=\dfrac{81}{375}\\\\\\r^3=\dfrac{27}{125}\qquad \leftarrow simplied\\\\\\\sqrt[3]{r^3} =\sqrt[3]{\dfrac{27}{125}}\\ \\\\r=\dfrac{3}{5}

Next, let's find a₁

a_1\bigg(\dfrac{3}{5}\bigg)=375\\\\\\a_1=375\bigg(\dfrac{5}{3}\bigg)\\\\\\a_1=125(5)\\\\\\a_1=625

Lastly, Use the Infinite Geometric Sum Formula to find the sum:

S_{\infty}=\dfrac{a_1}{1-r}\\\\\\.\quad =\dfrac{625}{1-\frac{3}{5}}\\\\\\.\quad =\dfrac{625}{\frac{2}{5}}\\\\\\.\quad = \dfrac{625(5)}{2}\\\\\\.\quad = \large\boxed{\dfrac{3125}{2}}

7 0
3 years ago
A drainage basin bordering the sea has an area of 7500 km2 . The average precipitation for this drainage basin is 900 mm year-1
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Answer with Step-by-step explanation:

The basic water balance dictates that "Amount of water flowing into the basin should be equal to the amount of water flowing out of it".

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P = precipitation

I = Infiltration losses in the basin

E = Evapotranspiration

Q = is outflow from the basin

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900=E+\frac{22.5\times 10^{8}}{7500\times 10^{6}}\times 1000+100\\\\900=E+300+100

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From the above equation we get

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The evaporation in cubic meters per year is

E'=0.5\times 7500\times 10^{6}=3750\times 10^{6}m^3/year

7 0
4 years ago
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