If Paul's height is equal to 69.4 inches, we can plug this value into the equation for h and solve for the length of his tibia bone, t.
h = 2.4t + 32.2 (given)
69.4 = 2.4t + 32.2 (substitute)
37.2 = 2.4t (subtract 32.2 from both sides)
15.5 = t (divide both sides by 2.4)
Since there is a 5 in the hundredths place, we round up to 16.
Answer:
The approximate length of Paul's tibia bone is 16 inches
