This one should have come before the other one. We apply the cone formula
![V = \frac 1 3 \pi r^2 h](https://tex.z-dn.net/?f=%20V%20%3D%20%5Cfrac%201%203%20%5Cpi%20r%5E2%20h)
![V = \frac 1 3 \pi(15.5)^2 (18.6) \approx 4679.6 \textrm{ cubic meters}](https://tex.z-dn.net/?f=V%20%3D%20%5Cfrac%201%203%20%5Cpi%2815.5%29%5E2%20%2818.6%29%20%5Capprox%204679.6%20%5Ctextrm%7B%20cubic%20meters%7D)
Hello from MrBillDoesMath!
Answer:
11/ 1009 (.0109 approximately)
Discussion:
99/9081 = => as 9081 = 9 * 1009 = 3 * 3 * 1009
99/ ( 3 * 3 * 1009) =
(99/(3*3)) * (1/1009) =
(99/9) * (1/1009) =
11/ 1009 =
.0109 approximately
Thank you,
MrB
Answer: Refer to the picture I've attached.
Step-by-step explanation:
As far as I know a pyramid net has a square in the centre and 4 triangles, each joining an edge of the square.
Hope this makes sense and helps. :)
Gh is a half of DF because it is a midline
2(3x-4)=9x-59
6x-8=9x-59
3x=51
X=17