96 divided by 4 is 24
3times 24 is72
And 72 is 3 times 24
And 72plus 24 is 96
So your answer is length 72
Wide24
Well, i would use the distance formula to find the distance between the two points. Only issue- you do not have the other point, so lets find it!
We have the point 4,6. 4 is the x, and 6 is the y.
Lets start with 4 since the x works with the left and right aspect of the location. It says M has been translated 8 units to the left, meaning we go back 8. So if we are at 4, and we go back (A.K.A. Subtract) 8, we will be at -4.
Now lets move onto the y, which works with the up and down aspect of the location. It says M has been translated 9 unites down, meaning the point will be heading down and getting smaller. So if we are at 6, and we go down (A.K.A. subtract) 9, then we will be at -3.
So now we have the coordinates of point M (4,6) and point M' (-4,-3) so we can now complete the distance formula!
The distance formula helps determine the distance between two points. It looks like this: D = √(x₂-x₁)²+(y₂-y₁)²
Though it does not matter which order you use the coordinates in, i am choosing to use M and then M'.
So, starting with the X, X₂ will be -4 and X₁ will be 4.
Again, starting with the Y, Y₂ will be -3 and Y₁ will be 6.
So, the formula plugged in will look like this: d = √(-4 - 4)² + (-3 - 6)²
Solving it out, we first need to work within the parenthesis. Can you solve it?
Our outcome will be this: -8² + -9². But, since we are squaring (And a negative times a negative equals a positive) you can just write 8² + 9²
8²= 64
9²= 81
64+81 = 145.
So, the distance between point M and point M' would be 145 units
Hope this helps!
If it does not, please let me know so i can try to help!
Answer:
hope this helps
Step-by-step explanation:
Answer:
a.
<u>Increasing:</u>
x < 0
x > 2
<u>Decreasing:</u>
0 < x < 2
b.
-1 < x < 2
x > 2
c.
x < -1
Step-by-step explanation:
a.
Function is increasing when it is going up as we go rightward
Function is decreasing when it is going down as we go rightward
We can see that as we move up (from negative infinity) until x = 0, the function is increasing. Also, as we go right from x = 2 towards positive infinity, the function is going up (increasing).
So,
<u>Increasing:</u>
x < 0
x > 2
The function is going down, or decreasing, at the in-between points of increasing, that is from 0 to 2, so that would be:
<u>Decreasing:</u>
0 < x < 2
b.
When we want where the function is greater than 0, we basically want the intervals at which the function is ABOVE the x-axis [ f(x) > 0 ].
Looking at the graph, it is
from -1 to 2 (x axis)
and 2 to positive infinity
We can write:
-1 < x < 2
x > 2
c.
Now we want when the function is less than 0, that is basically saying when the function is BELOW the x-axis.
This will be the other intervals than the ones we mentioned above in part (b).
Looking at the graph, we see that the graph is below the x-axis when it is less than -1, so we can write:
x < -1
Angle 4 is 77 degrees. Since angles 1, 2, and 3 must add up to 180 degrees, and angles 3 and 4 must also add up to 180 degrees, angles 1 + 2 must be equal to angle 4
