Just #14 plz thanks!!!
1 answer:
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Distance between points 
and 
is
Distance from H to B:
![[tex]d=\sqrt{(10-(-3))^2+(1-(-9))^2}=\sqrt{169+100}=\sqrt{269}](https://tex.z-dn.net/?f=%5Btex%5Dd%3D%5Csqrt%7B%2810-%28-3%29%29%5E2%2B%281-%28-9%29%29%5E2%7D%3D%5Csqrt%7B169%2B100%7D%3D%5Csqrt%7B269%7D)
d=\sqrt{(1-(-3))^2+(10-(-9))^2}=\sqrt{16+361}=\sqrt{376}[/tex] units.
Distance from Z to B:
units.
Horse Z is closer to the barn.
(The conversion to meters is not required; the question does not ask for actual distances, so "units" is OK.)
Distance from H to B:
Distance from Z to B:
Horse Z is closer to the barn.
(The conversion to meters is not required; the question does not ask for actual distances, so "units" is OK.)
Answer:
60
Step-by-step explanation:
1, Extand line y for which y intercepts CB at point K
2, line y is a straight line and thus KAB=180-110=70
3, AY parallel to CX thus angle CKA=130 which is a alternative angle of BCX (if you can't see then try to extend CX as well
4,BKA=180-130=50 as BC is a straight line
5, the sum of interior angle of a triangle is 180, and we have KAB and BKA, thus angle ABC = 180-KAB-BKA=180-70-50=60
