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Iteru [2.4K]
3 years ago
13

How would i solve

Mathematics
1 answer:
ohaa [14]3 years ago
3 0
To use the elimination method, the coefficient of one variable in one equation must be the opposite number of the coefficient of the same variable in the second equation.

4x-3y=8 \\
5x-2y=-11

Here you can multiply the first equation by 2, and the second equation by -3.

4x-3y=8 \ \ |\cdot 2 \\
5x-2y=-11 \ \ |\cdot (-3) \\ \\
8x-6y=16 \\
-15x+6y=33

Now you just add the equations by sides and solve for one variable.

8x-6y=16 \\ \underline{-15x+6y=33 } \\
8x-6y-15x+6y=16+33 \\
8x-15x=16+33 \\
-7x=49 \\
x=-7

Now you solve for the other variable by substituting -7 for x in one of the equations.

4x-3y=8 \\
4 \cdot (-7)-3y=8 \\
-28-3y=8 \\
-3y=8+28 \\
-3y=36 \\
y=-12

You could choose x at the beginning as well. Then you'd have:
4x-3y=8 \ \ |\cdot (-5)\\
5x-2y=-11 \ \ |\cdot 4 \\ \\
-20x+15y=-40 \\
\underline{20x-8y=-44 \ \ \ \ \ \ } \\
-20x+15y+20x-8y=-40-44 \\
15y-8y=-40-44 \\
7y=-84 \\
y=-12 \\ \\
4x-3y=8 \\
4x-3 \cdot (-12)=8 \\
4x+36=8 \\
4x=8-36 \\
4x=-28 \\
x=-7

So the answer is:
x=-7 \\ y=-12
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The answer to your questions is below

Step-by-step explanation:

4.-

In a 45°-45°-90° triangle, the length of the legs are "x" and the length of the hypotenuse is x\sqrt{2}

Then, in this problem, the length of the leg is 7 then the length of the hypotenuse will be 7\sqrt{2}

5.- In a 30°-60°-90° triangle, the length of the hypotenuse is 2x, the length of the longer leg is x\sqrt{3} and the length of the shorter leg is x.

In this problem we have the length of the hypotenuse = 20 and find x.

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6.- nonzero

7.- hypotenuse = 20 cm

     Find x

                         2x = 20

                           x = 20/2

                          x = 10

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4 0
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A. A variable

Step-by-step explanation:

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