X represents the length of a deck. There are three parts to this equations. The 1. width, 2. the length, and 3. the 5 feet shorter. Using the key words, y = the width of a deck (uses the term is which means =) So that takes the width part out of the equation. Then, 5 feet shorter means -5 than a number. That takes away the 5 feet shorter part of the equation. That leaves x to equal the length of the deck.
Idk tbh man I think sumbody else will answer
Answer:
<h2>
CYLINDER</h2>
Surface Area = 471.2 cm^2
<h2>
TRIANGULAR PRISM</h2>
Surface Area = 60.75 m^2
Step-by-step explanation:
<h2>
CYLINDER</h2>
The surface area formula for a cylinder is π x diameter x (diameter / 2 + height), where (diameter / 2) is the radius of the base (d = 2 x r), so another way to write it is π x radius x 2 x (radius + height). ( π =3.14 )
FORMULA:
π x 5 x 2 x 15
WORK:
π x 5 = 15.7
15.7 x 2 = 31.4
31.4 x 15 = 471
<h2>
TRIANGULAR PRISM</h2>
The surface area formula for a triangular prism is 2 * (height x base / 2) + length x width1 + length x width2 + length x base.
FORMULA:
2 x (2.5 x 1.5/2) + (6 x 4) + (6 x 4) + (6 x 1.5)
WORK:
(2.5 x 1.5) = 3.75/2 = 1.875
1.875 x 2 = 3.75
(6 x 4) = 24
(6 x 4) = 24
(6 x 1.5) = 9
3.75 + 24 + 24 + 9 = 60.75
<u><em>Answer:</em></u>
A. $4397.9
<u><em>Explanation:</em></u>
We are given that Kendra sold 200 shares and that the price per share was $22.1
<u>This means that:</u>
Total value = 200 * 22.1 = $4420
Now, we know that the broker charged 0.5% commission on the total value
<u>This means that:</u>
Broker's charge = 0.5% * 4420 = 0.005 * 4420 = $22.1
<u>Therefore,</u>
Kendra's return = Total value - broker's charge
Kendra's return = 4420 - 22.1 = $4397.9
Hope this helps :)
Answer:
Angle A = Angle Y
Angle B = Angle Z
Angle C = Angle X
AB = YZ
AC = YX
BC = ZX
Triangle ABC = Triangle YZX
Step-by-step explanation:
Find this by looking at the corresponding parts on the other triangle. They have the same marking on them. Make sure that when answering for segments or triangles that the order is the same on both sides.