Factor
in form
ax²+bx+c form
use the ac method
1. mulitply a and c
2. factor the result such that the 2 factors add to b
3. split b into those 2 factors
4. group the terms
5. undistribute common factors
6. undistribute again
first multiply ac
4 times 5=20
now
what 2 numbers multiply to 20 and add to 12
2 and 10
4x²+2x+10x+5
group
(4x²+2x)+(10x+5)
undistribute
2x(2x+1)+5(2x+1)
undistribute the (2x+1)
(2x+1)(2x+5) is factored form whih you have there, nice
Answer:
C) y = -cos(x) +2
Step-by-step explanation:
The centerline is 2, so 2 is added. That leaves out choices A and B.
There is a minimum (not a maximum) at x=0, so the multiplier is negative, eliminating choice D.
The correct equation is that of C: y = -cos(x) +2.
Standard form of a circle" (x-h)²+(y-k)²=r², (h,k) being the center, r being the radius.
in this case, h=-2, k=6, (x+2)²+(y-6)²=r²
use the point (-2,10) to find r: (-2+2)²+(10-6)²=r², r=4
so the equation of the circle is: (x+2)²+(y-6)²=4²
Here is the equation to find that answer A=bh+2ls+ib i got it off line if its not right im sory
To simplify, you just condense all of the values with the same variable, based on the signs of those values.
In this example,
6y + 5z + 8y - 3z
is the same as
6y + 8y + 5z - 3z
which can be simplified to
14y + 2z
which is the answer to your question.
Hope that helped =)
