4 years ago

Help!!

1 answer:

8 0

False

(5,5)
y < x + 3
5 < 5 + 3
5 < 8 (correct)

(5,5)
y > -2x - 1
5 > -2(5) - 1
5 > -10 - 1
5 > -11 (correct)

so (5,5) is a solution..and there are many more

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olga_2 [115]

Answer:

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7 0

3 years ago

Read 2 more answers

I dont understand this at all. I really need help!

Westkost [7]

Hello!

$\large\boxed{x^{4}}$

Recall that:

$\sqrt[z]{x^{y} }$ is equal to $x^{\frac{y}{z} }$ . Therefore:

$\sqrt[3]{x^{2} } = x^{\frac{2}{3} }$

There is also an exponent of '6' outside. According to exponential properties, when an exponent is within an exponent, you multiply them together. Therefore:

$(x^{\frac{2}{3} })^{6} = x^{\frac{2}{3}* 6 } = x^{\frac{12}{3} } = x^{4}$