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Tom [10]
3 years ago
13

Write an expression for the calculation double 2 then add 5

Mathematics
2 answers:
jenyasd209 [6]3 years ago
6 0
2 double is 4 and 4 plus 5 is 9

Hope it helps:)
Sergio [31]3 years ago
4 0
So,

"double 2"
2(2)

"add 5"
+ 5

Therefore, the whole expression would be:
2(2) + 5

If you wanted to evaluate it, it would come out like this.
4 + 5
9
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Identifying equivalent statements and negations of a conditional statement: help
Vitek1552 [10]

Answer:

1: Equal

2: Negation

3: Negation

4: Neither

Step-by-step explanation:

Sorry if I got any of them wrong

6 0
3 years ago
Find area of the composite figure..
saveliy_v [14]

Answer:

627square inches

Step-by-step explanation:

Area of the composite figure.. = area of triangle + area of parallelogram

Since the triangle is an equilateral triangle;

Area of the triangle = r²sintheta

Area of the triangle = 18²sin60

Area of the triangle = 324sin60

Area of the triangle  = 324(0.8860)

Area of the triangle = 280.584 square in

Area of the triangle = 281 square inches

Area of parallelogram = absintheta

Area of parallelogram = 20(20)sin60

Area of parallelogram = 400(0.8660)

Area of parallelogram = 346.4square inches

Area of parallelogram = 346 square inches

Area of the figure = 346  + 281

Area of the figure  = 627square inches

3 0
3 years ago
Find the probability of throwing 9 with two dice.
ololo11 [35]
Total number of possible outcomes of throwing two dice = 6×6 = 36
Number of outcomes of getting 9 i.e, (3+6),(4+5),(5+4),(6+3) = 4

P = \frac{Number \: of \: favourable \: outcomes}{ Total \: number \: of \: possible \: outcomes}

P (throwing \: 9) = \frac{4}{36} = \frac{1}{9}
6 0
3 years ago
Evaluate the given expression if w = 6 and z = -3.
LenaWriter [7]
The answer will be 75
-3*-3*-3*-3=81
Z^4-w
81-6=75
5 0
3 years ago
Read 2 more answers
A new neighborhood activity complex is being built in erie. The perimeter of the rectangular playing field is 256 yards. The len
maw [93]

Answer:

The length of the rectangular playing field is 84 yards and the width is 44 yards

Step-by-step explanation:

Let

x ------> the length of the rectangular playing field

y -----> the width of the rectangular playing field

we know that

The perimeter of the rectangular playing field is equal to

P=2(x+y)

P=256\ yd

so

256=2(x+y) ------> equation A

we have that

x=2y-4 -----> equation B

Solve the system by substitution

Substitute equation B in equation A and solve for y

256=2(2y-4+y)

128=3y-4

3y=128+4

3y=132

y=44

Find the value of x

x=2(44)-4=84

therefore

The length of the rectangular playing field is 84 yards and the width is 44 yards

4 0
3 years ago
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